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  1. T

    Quad polynomials help

    I'll just give you hints. 1) Use discriminant, which has to be less than 0 such that it has no roots. 2) let X= 5^x (it's reducible quadratics)- Solve 5X^2-26X+25=0
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    hsc mark

    Lol, this guy's a beast. +1
  3. T

    When questions ask you to "Draw a neat sketch"

    Haha, "draw a neat sketch". You can practice in Biology aka your bludge period; they say practice makes perfect :D
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    mathematical induction step 4

    Says the guy that couldn't even do an easy Ext 2 TAKE HOME ASSIGNMENT.
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    mathematical induction step 4

    Don't think you can skip the step as it's a conclusion to your question but you can always leave out "Step4" :).
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    When questions ask you to "Draw a neat sketch"

    You can equate your small thing for the 0.5cms. No worries buddy. Thank me later. You'll be fine, just do what you did at the library. haha.
  7. T

    Planino's a girl. Ask her here yourself...

    Planino's a girl. Ask her here yourself: http://community.boredofstudies.org/member.php?u=1611062349 Enjoy ;).
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    Polynomial Questions

    I might be wrong but this is what I think (replaced y with c): ii) LHS= a^n+3 + b^n+3 + c^n+3 + k(a^n+1 + b^n+1 + c^n+1) + a^n + b^n + c^n (expand and simplify. Note: a^n+3 = a^3 x a^n = a^n(a^3+ka+1) + b^n(b^3+bk+1) + c^n(c^3+kc+1) = a^n(0)+b^n(0)+c^n(0) since a,b and c are...
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    Geometric applications of calculus help!

    Don't get throw off by the phrase "monotonically increasing". It's just asking "for what values of x is the curve always increasing". y'=3x^2-6x-27 3x^2-6x-27>0 (draw graph) (3x+3)(x-9)>0 x<-1 and x>9.
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    Geometric applications of calculus help!

    1. f(x)= x^3-3x+4 f'(x)=3x^2-3 For decreasing: 3x^2-3< 0 therefore: x^2-1<0 (draw graph) -1< x <1 2. f(x)=x^3+12x^2+45x-30 f'(x)=3x^2+24x+45 For increasing: 3x^2+24x+45>0 (3x+9)(x+5)>0 (draw graph) x <-3 and x >-5 If you graph the inequality on a number line, you'll be able see it. Hope this...
  11. T

    Newtons method Q

    a) let P(x)= 2x^2+x-2=0 P(0)= 0+0-2 = -2 which is negative. P(1)= 2+1-2 = 1 which is positive. Since there is a switch in sign, curve is continuous. Therefore, there is a root between 0 and 1. b) P(0.5)= 2(0.25)+0.5-2= -1 which is negative. From a), P(1) is positive. Therefore root is between...
  12. T

    Area between Function and Axis Help!!!

    Yeah I guess so for this example...
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    How to study for maths?

    First of all, to be blunt, do not post another one of your assignments up in the future in hope for just answers. Have a genuine attempt at least... Studying maths...Not very happy about how I go about it to be honest haha, but I've had a fair share of good/bad experiences. I would recommend...
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    Area between Function and Axis Help!!!

    Correct me if I'm wrong (it's been a while since I last did area bounded x/y-axis), but OP, the example you gave must include borders otherwise the area is differing.
  15. T

    Polynomials.

    Oh right, completely forgot about that. Thanks for your help :P
  16. T

    Polynomials.

    Hey guys, need some help and clarification. So you're asked to prove a quadratic has distinct roots- that would just be discussing that the discriminant is greater than 0. How do you go about explaining that a cubic equation and powers beyond have distinct roots? Do you have to relate it back to...
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    Do you have to learn proofs for different formulas?

    You probably won't be asked for the proof in 2u but most likely in 3&4u; for some formulas (can't think of one atm), it's best that you learn how to derive them.
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    Locus & The Parabola help

    Lol I know who you are :) But: For these questions, you have to split it into cases Given that the endpoints are (-2,3) and (6,3) -> the y ordinates don't change meaning that the equation of the parabola is in the form (x-k)^2 = +- 4a(y-k) Latus rectum length =4a = 6--2 =8 Sub that in and one...
  19. T

    How are u 2013'ers finding MX2?

    Mr Gee and Mr Huxley.
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    How are u 2013'ers finding MX2?

    lol not sure I'm intimidated. Just scared whether I'd be able to keep up with the workload. haha.
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