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How did everyone find the exam? Personally did the ATB module and found it to be very very straightforward.

What’s your take on 3U then?

Last year q14 had like 7 marks of differentiating and 53 went to E4

Yeah should be 51ish. Hoping I can crack 92 with a 56/57 then;)

I think it will be closer to 51,52. On par with 2016 I think but not as difficult as 2009

What would 57 align to? Would it be enough for E4?

First consider P(draw)= 1/5. As regardless of who goes first there will be 1/5 chance the second person gets the same number. That leaves 4/5 left- now since we don't know who goes first or any other information they have equal chance of winning. Therefore, 1/2 * 4/5= 2/5.

I'm thinking it will be a hard binomial probability 'game' style question.

The committees setting the papers are independent I believe. Might mean the difficulty was purely coincidental. But to be honest for a decent student the 2U paper wasn't that challenging. Not sure about 4U obviously

After seeing those answers I think I got between 94-96. Would what that align to?

Yeah it's the same answer I checked 5.13 radians

https://www.smh.com.au/education/hardest-question-i-ve-ever-seen-hsc-maths-exam-reasonable-until-last-question-20181025-p50bv2.html

For theta I found x to be root 200/3 or something like that. Then I considered that the curved surface area of cone is equal to the area of the cut out sector they gave us. So I just found the max value of the the cone and then used the area of sector to find theta by equating the areas. I got...

Look at raw marks.org never in recent history has requirement b6 been higher than 88. I'm thinking our paper was much harder than 2014 and the last couple of years

Yeah I was like what isn't this 2U. Re cutoff it was definitely harder than 2016 and 2017 so I'm thinking low 80s for b6 cutoff.

Thinking I got around 96,97 what would that align to? For shoe multi it was 1/7 right? Also for the max min was I like the only person who equated the curved surface area of the cone and the sector area of the circle to find theta lol there must have been an easier way

Displacement is represented by the area under the velocity curve. So we just calculate the area of the triangle we see i.e. 1/2 * 4 * 8= 16. But the particle starts at 2 so we have 16+2=18. Thus D

I always do multi choice last in maths exams.

Blit probably knows better than me but I would interpret that as requiring two distinct headings from Operations strategies; i.e. you would do global strategies and the four subpoints and then you would pick another like quality management and cover the three subpoints under that as well.

Around 83/105