Search results

I would think D because if a country is experiencing a boom its likely that its currency is appreciating. But if a boom means an appreciation, then exports are going to become more expensive so there is a 'speed limit' on growth. Hence a gov't/bank would artificially depreciate the currency so...

i thought business studies wasnt offered at baulkam hills

to have easy to remember acronyms go to an anagram solver like http://www.ssynth.co.uk/~gay/anagram.html and type in the letters then you can pick whichever is the easiest to remember

assume 4^k-1-7k>0 then you have to prove for n = k+1 that 4^{k+1}-1-7(k+1)>0 so use the assumption \\4^{k}-1-7k>0\\\\ \frac{4^{k+1}}{4}-1-7k>0 \\\\ 4^{k+1}-4-28k>0 then you try and make everything look like what you are trying to prove 4^{k+1}-4-28k>0\\\\ (4^{k+1}-1-7k-7)+4-21k>0\\\\...

out of 105? adv btw

use e^ix to show off

wat

umad

what raw marks go to 100/100 and 50/50 for maths extension 1 and 2?

you better try to learn yourself fast

prepared responses for economics?

very nice thanks

i find perm combs the hardest

least challenging = graphs and integration

no

the harder questions are ones which combine topics

are you in year 11?

thanks

can someone reupload sydney grammar 4u 2006 solns

\\y=x^{\frac{1}{3}}\\ \\ \frac{dy}{dx}=\frac{1}{2\sqrt[3]{x^2}} \\ \\ x\rightarrow 0^+\\ \\\frac{dy}{dx}\rightarrow\infty \\\\\ x\rightarrow 0^-\\\\ which\ is\ =\ to\ approaching\ from +ve\ side\ because\ of\ square\ term\\\\ \frac{dy}{dx}\rightarrow \infty\\ \\ \i.e.\ gradient\ of\ tangent\...