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more like, The Red in the Sky is Ours

a velvet creation is better. mirrorworlds is still good tho

Re: Australian Mathematics Competition yeah, I would say that's it. I was sure i'd tested this set up too =/

Re: Australian Mathematics Competition does anyone know/has anyone posted the answer for Q29? all I can think of is having a symmetrical arrangement of the stations, like if you placed a pentagon, square and inverted triangle on a circular railway track. this gives a value of 189

Re: Australian Mathematics Competition c), which was 1-rt3+pi/3 iirc

Re: Australian Mathematics Competition Iruka posted their solution to Q30 on the previous page http://community.boredofstudies.org/238/appreciating-beauty-elegance-extracurricular-topics/216960/australian-mathematics-competition/17.html#post4503758

only if they started it

Re: Australian Mathematics Competition for the overlapping circles one, i drew, separately, two circles overlapping at opposite corners, and two circles overlapping at adjacent corner. from these, i found the values of different areas of the shapes in the four overlapping circles, and could...

I might go, cos of cynic and such. I need to listen to some more of the bands going to see if I like them.

Re: Australian Mathematics Competition I actually get 84 for this one * my solution:

Re: Australian Mathematics Competition i figured it out with elimination (starting with the last digit) (btw, i didn't actually sit the test)

Re: Australian Mathematics Competition he means don't count (1,7)etc. for both "x is an integer", and "y is an integer", as you'll count it twice

Re: Westpac Maths Comp marathon A rectangular prism 77 x 81 x 100 is cut into cubes of edge 1 by planes parallel to the faces of the prism. A given internal diagonal pierces how many of these cubes? (A) 255 (B) 256 (C) 257 (D) 258 (E) 259 +ty kurt for the link to the papers. I'm gonna do them...

Re: Westpac Maths Comp marathon is the answer to this 50? figure out my notation; ) \\ \alpha =4\\ \alpha ^2 = 10\\ \alpha ^3 = 22\\ \alpha ^4=???\\ \\ 1) (\alpha ^2)^2=\alpha ^4+2\alpha ^2\beta ^2=100\\ 2) (\alpha )(\alpha ^2)=\alpha ^3+\alpha \beta ^2=40\\ 3) (\alpha )(\alpha ^3)=\alpha...

trick question, time and space are mere illusions

i haven't done these for ages, but I would think: your forces should -add- to give the centripetal force. if you want to make it so the forces sum to zero, then you would add the negative of the centripetal force (i.e. an outwards force, which I think is then termed the centrifugal "force"?)...

are there any school subjects that don't suck tho? just apply da formula better

that should be all you need. just draw in the radius of the circle to that point and you have a right angled triangle, so you can get the angle

just work backwards and use the (x-y)2 >= 0 inequality (x-y)^2\geq 0\\ (x+y)^2\geq 4xy\\ \frac{y+x}{xy}\geq \frac{4}{x+y}\\ \frac{1}{x}+\frac{1}{y}\geq \frac{4}{p} and (x-y)^2\geq 0\\ x^2+y^2\geq 2xy\\ and\ \\ (x+y)^2\geq 4xy\\ (x^2+y^2)(x+y)^2\geq 8x^2y^2\\ \frac{x^2+y^2}{x^2y^2}\geq...

the ATAR score is determined from year 12 subjects. 50% is from inschool assessment (based on your rank) and 50% from the HSC assessment at the end of year 12 (generally a test for each subject). You get a score from each subject, which is scaled according to how people went, and then your best...