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No problems your welcome :)

so you put x=-2: (-2)^4 + p(-2)^3 + q(-2) + 1 = 16-8p-2q+1 = -8p-2q+17

basically all you need to do is apply the remainder theorem. So all you do is sub in x=1 into the equation so you get: (1)^4 + p(1)^3 +q(1) + 1 = 1+p+q+1 = p+q+2 and we know that the remainder is 3 i.e. Q(x) = 3 therefore p+q+2 = 3...(1) Do the same thing but now sub in x= -2 to get: -8p-2q+17...

Thank you very much, thats the second time u helped me:D

Hey, The way to solve this question would be first look at where the curve crosses the x axis at x=4. so i put x=2 in f(x^2) which would yield 4. So at x=2 the y coodinate is 0 as that was what it was for 4. now repeat for a couple of coodinates. e.g for x=9 the curve is approaching the...

http://www.boardofstudies.nsw.edu.au/hsc_exams/hsc2010exams/pdf_doc/2010-hsc-exam-mathematics-extension-1.pdf I need help with Q7)C)

lol ok thank you soooo much

Can you help me out with multiple choice q18 2009 HSC

Wow, too much stress. Thanks a lot, really appreciate it :)

That's what i thought! but the answers say that it's (A) which is 0.2

Hey guys, could someone please explain the multiplier question in the 2010 HSC. It's question 12 of the multiple choice.

thank you

Hi, i am unsure what to write about if this was an essay question i looked at syllabus but dont get it Examine the links between the key BoP categories and the trends associated with the BoP in the Australian economy

Thanks a lot mate. was expecting you to comment ;)

hi does anyone know how to download LaTeX?

Thx man

are each module in the hsc marked by a different marker or all 3 are marked by the same

hey, thx for the 4unit multiple choice do you have 3unit by any chance

Those are generally tough, especially the two unit ones, if you want I help you out with it.

That's alright, its only year 11, did you have problems with anything else?