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Re: MX2 Integration Marathon 1?

The whole graph gets shifted by pi/4 to the right. So the asymptotes are just pi/2 +pi/4, 3pi/2 + pi/4 etc for all the asymptotes

Hey, so for rates of change, to find the rate of change after a time period if you have the quantity can you just differentiate and then sub in the time, or do you have to use (change in quantity)/interval of time?

Re: MX2 Integration Marathon Use the property that makes it the integral of 0 to 2 f(x)+f(-x), then times the f(-x) by e^x on both sides and add the f(x) and f(-x) and factorise out the e^x +1, making it the integral of x^2?

Re: MX2 Integration Marathon integrate from 0 to pi/2 (1+sin2x)^.5

Re: MX2 Integration Marathon integrate 4/(x^2 +2x-1)

Re: MX2 Integration Marathon Yeh but there already is one cosx on the denominator so you put in the dx=-2udu/cosx, meaning the denominator goes to cos^2x, then through the fact that sinx =1-u^2, you see that cosx=root(1-(1-u^2)^2)^.5, meaning cos^2x=1-(1-u^2)^2=2u^2-u^4 Then you get the...

Re: MX2 Integration Marathon For your t results wouldn't there be a root (1+t^2) on the top though because 1+sinx would equal (1+t)^2/1+t^2, and the other 1+t^2 (which you used) im assuming is from dx=2dt/1+t^2 and also where is the two from that

Re: MX2 Integration Marathon Do you times by (1-sinx)^.5 on both sides which gives you (1-sinx)^.5 /cosx, then you use u^2=1-sinx, which ultimately gets you to pi/2?

Re: MX2 Integration Marathon for integral of (1+cosx)^.5 make 1+cosx=2cos^(2)x/2, then root it to make it (2)^.5 cos(x/2) integrate to get 4(2)^.5?

Re: MX2 Integration Marathon it should be 1/2 instead of 2 in your 4th line

Re: MX2 Integration Marathon integrate from pi/2 to 0, 1/(2sin^x + cos^2x),

BUMP

Hey, I have an essay I have to do really soon which is about how construction is significant to meaning and I was just wondering can setting be considered a part of construction?

How do you solve the integral of cos^(5)x/(cos^(5)x+sin^(5)x) between pi/2 and 0

Hey so, When a question asks why does say f(x) have an inverse function, where f(x)=x^3 or something like that, is all you have to say to get full marks, because for every x value there is one y value? Also in circle geo, can you just say thales' theorem instead of angles in a semicircle...

=(a-2)^2-9b^2 =(a-2+3b)(a-2-3b)

Hey I have my eco half yearly tomorrow and I have no clue how to do this question It is from the 2010 hsc, the answer is d

I think everyone is confused thinking that the ranking of the school is 147. That is just the number of exams sat and the school actually got 0% DA http://resources.news.com.au/files/2012/12/23/1226542/679077-hsc-full-list.pdf

Hey, What happens to the graph when you find f(x^2) of a graph????