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lol

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What is your question? Finding the inverse of f(x) = x+(1/x) ?

Sibilance is often employed to emphasize an idea

Silent shock - sibilance

Everything so both left and right, 0=6t^2/5+4t+5. Get rid of the denominator multiply throughout by 5, 0=6t^2+20t+25

<a href="http://www.codecogs.com/eqnedit.php?latex=cos^2(45) = \left (\frac{1}{\sqrt{2}} \right )^{2} = \frac{1}{2}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?cos^2(45) = \left (\frac{1}{\sqrt{2}} \right )^{2} = \frac{1}{2}" title="cos^2(45) = \left (\frac{1}{\sqrt{2}} \right...

<a href="http://www.codecogs.com/eqnedit.php?latex=1.~2\sqrt{2} - 2 ~~~~~~~~~~2.\sqrt{6}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?1.~2\sqrt{2} - 2 ~~~~~~~~~~2.\sqrt{6}" title="1.~2\sqrt{2} - 2 ~~~~~~~~~~2.\sqrt{6}" /></a>

Do you know your exact values?

<a href="http://www.codecogs.com/eqnedit.php?latex=\frac{tan45 @plus; tan60}{1-tan45tan60} = \frac{1 @plus; \sqrt{3}}{1 - \sqrt{3}} = -2-\sqrt{3}" target="_blank"><img src="http://latex.codecogs.com/gif.latex?\frac{tan45 + tan60}{1-tan45tan60} = \frac{1 + \sqrt{3}}{1 - \sqrt{3}} = -2-\sqrt{3}"...

k nps

Re: HSC 2012 Marathon :) <a href="http://www.codecogs.com/eqnedit.php?latex=x = -2\frac{1}{2} ~ and~\ddot{} x=-\frac{\pi^{2}}{4}x \\ Sub ~x ~in~,~\ddot{} x=-\frac{\pi^{2}}{4} *-2\frac{1}{2} = \frac{5\pi^{2}}{8} ~cm/s^2" target="_blank"><img src="http://latex.codecogs.com/gif.latex?x =...

Replace chemistry with legal and physics with business and ill drop SOR 1

when are you appearing in court?

Depends on how other people went, 75% could be the top mark.

lmaof

Wow i was just looking at videos of this and it definitely has that 'abandoned' feel.

well pi/6 is 30. so roughly between 0 and pi/2 more to the left. if that explains it...

<a href="http://www.codecogs.com/eqnedit.php?latex=\dpi{150} \int_{0}^{\frac{\pi}{3}}\textup{ sin}(2-\textup{x}) ~\textup{dx} \\ = \left [\textup{cos}(2-\textup{x}) \right ]_{0}^{\frac{\pi}{3}} \\ = cos(2-\frac{\pi}{3}) - cos(2) \\ \approx 0.9955 ~(4 dp)" target="_blank"><img...

<a href="http://www.codecogs.com/eqnedit.php?latex=Sub ~ v = 60 \\ e^{-0.4t} = \frac{-v@plus;80}{80} \\ -0.4t = \ln(\frac{2}{8}) \\ t= 3.466 ~(3~dp) \\Sub~ t~in~ x=80t @plus; 200e^{-0.4t} - 200 \\ x = 127m" target="_blank"><img src="http://latex.codecogs.com/gif.latex?Sub ~ v = 60 \\ e^{-0.4t} =...