You should be able to. I'm inclined to think its "3. Something else".
Last year when I was in first year, I enrolled in a 2nd year and 3rd year course for 2nd semester during the beginning of the enrolments (i.e. before we got our results) and those courses had sem 1 prerequisites.
That is if we...
yes, but if u only have 1 semesters results you obviously cant have your whole first year WAM, u can still have a WAM after 1 semester. In fact, if u apply for exchange for 2nd yr 2nd semester, (i.e. u would have to hand in your application before sem 2 results are out) then ur exchange...
What do u mean what does it mean?
Its pretty clear, not that I know how to do it.
They just want you to write a function that takes a "list" of complex values, and then it'll return the max modulus.
So you'll just have a function that found the modulus of every number in the list and then use...
lol slow down guys...
way too early to even think about WAM.
You can't tell anything until u do finals...
@b00m
i don't see why u need 2 semesters for WAM. If you have HD WAM after 1st sem 1st year theres a pretty good chance you'll stay HD WAM for 1st year since first year subjects are pretty...
if you have no intention of doing maths, and just wnat to focus on actuarial it is probably better just to do actuarial and do the honours year on that instead, because if u do advanced maths ur honours year will have to be on maths...
i think its got a lot tougher in the past 3/4 years, I know "asians" who have got under 99 -> med at unsw
I don't see why there would be more "non asians" under 99 in unsw med, unless its rural or something :S
X~Normal(70, 9^2)
We want x, such that P(X>=x) = 0.2.
Now, u standardise X. P(Z >= (x-70)/9) = 0.2
1 - P(Z < (x-70)/9) = 0.2
P(Z<(x-70)/9) = 0.8
Now u just look in the Z table, for the value that satisfies that, and solve (x-70)/9 for it.
gen eds are okay, theres so much stuff to choose from, hard not to find at least 2 things that are interesting. Don't think that they should count to WAM though, since it is kinda unrelated to my degree, but maybe hard to implement though.
1. It asks for expected value, not probability.
2. It's not simply a binomial. It's a distribution f(x) for example, where f(9)=0.5 and f(-9)=0.5. So Var(X)=E(X^2)-[E(X)]^2. Now E(X)=0 and E(X^2)=(-9)^2*0.5+(9)^2*0.5=81. So Var(X)=81.
3. Largest variance should be probability closest to 0.5...
its pretty much the same, theres a few different topics but overall u learn the same basic stuff...anyway, 1151/1251 is supposed to be only for actuary/finance ppl..so its not like 1151 is a "higher level" than 1141, or 1141 is a "higher level" than 1151, they're 2 different streams for...