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Consider each part of the inequality separately. When we add \frac{1}{\sqrt{n+1}} to all parts of inequality, the left part of the inequality becomes: \sqrt{n}+ \frac{1}{\sqrt{n+1}} &= \frac{\sqrt{n(n+1)}+1}{\sqrt{n+1}} \\ &= \frac{\sqrt{n^2+n}+1}{\sqrt{n+1}} \\ &\geq...

Re: 2012 HSC MX1 Marathon http://en.wikipedia.org/wiki/Tombstone_(typography)

If the question permits, finding stationary points help as well.

If you don't mind me asking, what level of statistics have you done? I agree applying hypothesis tests, finding ANOVA and doing regression is boring, but statistics is much deeper than this (eg. the theories of statistical inference, markov properties and martingales, SDEs) which is actually...

Employers generally don't care about the difficulty of the courses you do so marks are the only thing that matters. If you feel you will score higher with the lower version then do the lower version. Having said that, higher units usually scale better than lower ones to compensate for the...

The onus is on the student to check if they sent a corrupt file. It the tutor/lecturer can't read it, you get zero. No leniency should be shown.

+1 and at unsw as well

Its ironic as you are more likely to apply the bolded topics you listed in a statistics major rather than a pure maths major. I think the reason why you hate stats and probability at the moment is because it is not taught well in high school (just number bashing). In university, it is much more...

Re: 2012 HSC MX1 Marathon This is a 3D trig and PC is above the horizontal plane. Define G as the point the perpendicular from C meets the extended line of AB. The aim of the question is to show that CG/PG=sqrt(3)/5 Let x=AB so AP=2x Also BC=x and angle CBG=60. Then use simple trig to find...

Re: 2012 HSC MX1 Marathon Is a combinatorial argument acceptable? If so, then since: ^{2n}C_n= number of ways to choose n objects from 2n objects. One way to do so is to split 2n objects into 2 groups with n objects in each (Doesn't matter how its done) Consider number of ways of choosing k...

These can be simplied further....

EDIT: nevermind see above

Courses with numbers starting with 1 (eg. ACCT1501) are level I courses. These are usually cores courses and mostly done in first year (but you can do them in other years as well). Courses with numbers starting with 2 (eg. MATH2901) are level II courses which are usually done in second year...

Not always true (eg. 3 collinear points). Its more accurate to say that for any triangle, there exists a circle which circumscribes it.

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H Yes. If you want to do com/sci (either finance or actuarial for commerce), you can find sample plans there. Finance - http://www.maths.unsw.edu.au/futurestudents/finance-study-plan Actuarial -...

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H If you are serious about majoring in maths, do higher. You learn more and it scales better. Given your 4U mark, you should be fine with higher.

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H ^ yes, any course with MATH3###

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H Notice that there are 2 course codes for each subject. The 2nd one is the higher equivalent. Eg. MATH2011 (normal level) or MATH2111 (higher) - Several Variable calculus.

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H See here: For maths major in b sci http://www.maths.unsw.edu.au/futurestudents/science For advanced maths http://www.maths.unsw.edu.au/futurestudents/advanced-mathematics-science Explore the rest of the site...

Re: B Commerce/Science(adv MATH)[UNSW] versus B Commerce/Science (USYD) - which one?H Difficulty is dependent on which courses you are doing. Although for an adv maths degree you have to do "higher" courses, most people doing a b sci major in maths will end up doing higher courses anyway due...