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I am just going to point out this self contradiction here. How can you argue that women shouldn’t dress a certain way because it illicits a reaction and at the same time argue that people should publish satirical cartoon despite it illiciting a reaction?

Waiting for jazz519 to comment, but for Q25c) you should recognise that a condensation polymer is formed by linking N monomer chains which releases (N-1) water molecules in the process. Compute total polymer molecular weight based on the molecular weight of the N monomers and subtracting out the...

A related article https://www.smh.com.au/national/nsw/nsw-education-standards-authority-defends-cruel-hsc-maths-exam-20201030-p56a1v.html

Fun fact - For Maths Ext1 the very first question in the 2005 and 2006 HSC papers were basically identical but worth different marks (1 mark in 2005 and 2 marks in 2006)

Should be out in a few days. If you have any specific questions you want a solution for, ask it here. Good pick-up. There's actually a typo in that alpha and beta should not be equal (so the denominator is non-zero), rather than one being greater than the other which is a stronger condition...

If rigour is not important for the HSC markers then it would probably be sufficient to simply test one point to find c (i.e. most people would get full marks). However, the whole idea of testing for the different domains was for the sake of rigour (i.e. just in case there is some weird piecemeal...

Alternatively, you can just - Prove f(1) = g(1) and f(-1) = g(-1) where the derivative is undefined - Then solve for c in f(x) = g(x) + c, for one (or more) chosen x-values where the derivative is defined (e.g. x = 0.5)

A remark on Q13c)ii). It had a nice trap where you had to recognise that f'(x) and g'(x) are undefined at the points (1,0) and (-1,0) but these are points where the f(x) and g(x) are defined. So technically speaking you can only say that since their derivatives are -\frac{1}{x^2\sqrt{1-x^2}}...

It depends on whether you address the entire range of cos-1x or only the acute angle part.

The question said "By considering the reversed process and using part (ii)" so I'm not sure you will get full marks without doing that tbh

They used to let students keep the question papers (the parts where there are no responses written).

It's very wordy, but hopefully makes sense...

My solution to Q14b) if anyone is interested

In lieu of someone posting the paper, would anyone be able to outline (from memory) what each of those harder questions asked you to do or prove?

So you had to independently learn the 2d vectors topic from 3u while covering 3d vectors it in 4u?

Most common approach is to use the general term of one binomial multiplied by the general term of another, but with a different index variable. This is effectively the “double sigma” approach but without explicitly using that notation.

Or you could just solve for x to find the obtuse angle directly and then calculate sin 2x

A sum of n terms can be treated like a sequence. For example define the sequence {sn} where s_n=\displaystyle\sum_{k=1}^na_k

Boom. Here are the solutions and student results for the 2020 Mathematics Extension 1 BoS trials. Thanks to everyone who participated and for your patience! Once again, a reminder that whilst the questions are made to be as closely styled to the HSC exams as possible, this is NOT intended to...

...and SMH has another article on the last question of the Maths Ext2 paper just like last year https://www.smh.com.au/national/nsw/it-s-the-hardest-question-in-the-hsc-could-you-solve-it-20201027-p5696p.html