For the first one, you can use the substitution u=x+1.
For the second one, you will need to differentiate both sides of the substitution with respect to x and use the chain rule
u^2=4-x^2
\dfrac{du^2}{dx}=-2x
\dfrac{du^2}{du}\dfrac{du}{dx}=-2x
x\,dx=-u\,du
You can then substitute x dx and all...