Search results

Find the gradients of \dpi{120} y=-\sqrt{3}+2 and \dpi{120} y=x+1. Using the general form y=mx+b, where m is the gradient. Therefore the gradients for the equations are 0 and 1 respectively. substitute this into the formula \dpi{120} tan \Theta = \left | \frac{m_{1}-m_{2}}{1+m_{1}m_{2}}...

First you need to find the equation for acceleration, which is \dpi{120} \ddot{x}. \dpi{120} x=3sin(2t+5) \dpi{120} \dot{x}=6cos(2t+5) \dpi{120} \ddot{x}=-12sin(2t+5) Therefore it can be seen from the equation that the maximum value for the acceleration is 12 m/s^2.

(a,-2b) (3b,-a) in the ratio 3:-2 (NB: one of them is negative as it is divided externally) \dpi{120} \therefore \frac{-2Xa+3X3b}{3-2}=5 and \dpi{120} \frac{-2X(-2b)+3X(-a)}{3-2}=-10 \dpi{120} 9b-2a=5 and \dpi{120} 3a+4b=10 by solving simultaneously \dpi{120}...

A buffer is a solution with comparable amounts of a weak acid or weak base and its conjugate base or acid, this will form an equilibrium at a certain pH and will thus be able to maintain an approximately constant pH, and can resist the addition of significant amounts of strong acids or strong...

Just to add to your information, the breakdown of cellulose into glucose does not occur naturally and actually requires the use of cellulase enzymes. To test for Cl- ions in a solution, add silver nitrate or lead nitrate and if a precipitate forms chloride ions are present (the only insoluble...

You should be allowed, however it is very rare for them to give you a question in 3 unit where you must find what you need to substitute. But if you do, then you must show your working out, so state the formula and I believe that you should receive the marks.

This awareness of commercialisation can be paralleled to the context within which Frankenstein was composed as the theory of galvanism was just developed.

This is the general method for the students at the extension 2 level and it is usually not taught in 2 unit or extension 1 maths.

lol yeh I like the front cover because its got an integration question on it and I love that topic. Maybe that's why you like it =D

yeh I would recommend you get both because some exercises are better in Fitzzy den in Cam and visa versa. By the way, there is no point in buying it brand new, see if you can buy it off an ex-student or somethin, save a lot of money.

Yes Na2CO3 is non-hydrscopic while NaOH is, this is why a primary standard is needed to standardise solutions oh NaOH and this standard solution may be used to titrate other solutions. Just some extra information, Na2CO3 can come in two forms, anhydrous meaning it does not contain any water...

Lol if you do know me then you should know Tootoo ;)

lol at Woolworths, I work at Coles and I like it a lot more the Woolies =P

sorry with this question you form two equations; y=2x^{3}-3x^{2}-12x and y=k then you sketch the graph for y=2x^{3}-3x^{2}-12x and find where the line y=k will intersect three times with the function

sorry I did not read the question properly, there is another method to do it.

Do you mean that since Na2CO3 does not absorb moisture from the air (also as it has a high molar mass) it makes a good primary standard, whereas other compounds such as NaOH are not good primary standards as they absorb moisture from air.

MC answers are as follows; 1) C 2) D 3) D 4) A 5) A 6) C 7) D 8) C 9) A (although depending on your teacher D can be counted as correct as in the core sulfric acid is known to ionise completely although the true answer is the first ionisation goes to completion while the second ionisation does...

Simoooooooooooooooooo lol that you

oh and no offence taken =D

actually my parents are Egyptian and if I get 100% they will actually say congrats but then do that in everything else