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what do you reckon I would need to get for english to improve it

um well my school, only second year to do HSC, I think its around the 200-225

Can you please estimate my atar thanks =D English Adv: 75 (rank 4) Chemistry: 87 (rank 2) Physics: 83 (rank 2) Ext 1 maths (accelerated): got a mark of 92 Ext 2 maths: 89 (rank 1) Thanks so much

try keep your writing captivating while continual using the stimulus or stimuli throughout your writing.

Just try the questions you could not do, try them about 3 times(not straight after each other) until you do them without having to look at the answers.

medicine and surgery or actuarial studies =D

Btw my teacher ended up using pearson

Our teacher this year used the Cambridge one. She liked that better for some reason

Hey the sigma is just the expansion of the f(x). So; \dpi{120} f(x)=\sum_{k=1}^{n}(a_{k}^{2}x^{2}-2a_{k}x+1) \dpi{120} f(x)=\sum_{k=1}^{n}a_{k}^{2}x^{2}-\sum_{k=1}^{n}2a_{k}x+n Now as the equation is always above the x-axis or has a double root (ie, it just touches the axis), then the...

Yeh sorry my bad I'll fix it up

Well first ppm = mg/L ( thats the equivalent of 1 gram in 1 000 000 grams or a tonne) So 5 ppm is equal to 5mg/L. Also 1000ppb = 1mg and 1000mg = 1g, therefore 1 000 000ppb = 1g So again 5mg/L = 0.005 g/L With the graph, they generally give at least one standard value for an absorption, and...

\dpi{120} \frac{T_{k+1}}{T_{k}}> 1 can then be changed into \dpi{120} T_{k+1}> T_{k} all that means is the next term is greater then the term before it.

I would recommend them as they generally summarise really well while allowing you to answer questions. I would suggest macquarie and excel.

The method I use would be the same for either of the questions. However the only difference is for the greatest term you are given the x value so you substitue it into the equation and get \dpi{120} (1+3(\frac{2}{5}))^{7} \dpi{120} =(1+\frac{6}{5})^{7} You do not solve though, you then write...

There is generally just a set of rules for 1/f(x). They are f(x)=0 then \dpi{120} \frac{1}{f(x)}=\infty (therefore when the original function crosses the x-axis it will become asymptote) \dpi{120} {f(x)}=\infty then f(x)=0 (so it will cross the x-axis however this is not certain so when it...

When Alcaligenes eutrophus is used to produce this plastic, the extraction involves the breaking down of the bacteria's cells walls and separating this from the cell debris.

Definitely a high band 6 or the equivalent E4

That is really good, much appreciated =D

Because \dpi{120} sin(2t+5) has the range between 1 and -1, if you sketch the sine graph, as the 2t+5 in this case only dictates the period. So the highest value it can take is 1, therefore the greatest acceleration is for 12X1= 12 m/s^2. I just look at the amplitude of the graph \dpi{120}...

Because \dpi{120} sin(2t+5) has the range between 1 and -1, if you sketch the sine graph. So the highest value it can take is 1, therefore the greatest acceleration is for 12X1= 12 m/s^2. Just let me know if you still don't get it, I'll try explain it a different way =D