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I challemge anybody to a patato counting contest [and then a patato eating contest

shouldn't it be (6!/(2!2!))/5040 since there are 2 C's and 2 L's where are you getting the 3! from?

Don't just blindly go through papers. If you're constantly getting certain types of questions wrong work on that. Also instead of regurgitating formulae try and understand what you're doing.

what our teacher generally does is he gets us to do a couple of questions from maths in focus and then gives us all these hard examples on the board. There's nothing extremely bad about maths in focus, although some of Margaret's solutions are obviously incorrect its just very basic and you need...

hypothetically how would you solve it if the questions asked for the greatest positive coefficient without having to guess and check?

cool story bro

i think greatest coefficient implies a positive magnitude so usually the maximum coefficient would usually be when r = 7 but that gives us a negative term i think the greatest term is when r = 8 our teacher told us how to do these q's but i forgot -_-

Post the actual question so we can explain it but i assume the expansion is something along the lines of (a-b)^n the greatest coeff is when T(r+1)/T(r) > 1 i'm not sure what to do from there

Jeff est in horto

Hey Jeff I accepted Jason Min as a friend.

whoa, how did you work that one out? EDIT: I see what you did there jason minh very clever

it was worth 2 marks it's pretty much asking what can p be for there to be a solution for sinx = px or alternativley sinx - px = 0 when x= 0 0 - 0 = 0 regardless of p well atleast that's what i reasoned we'll probably find out the proper solution tomorrow

I think you got me confused with someone else.........

I have heard mixed responses for dell laptops, I had a friend who had their hard drive die twice on them and the customer support is horrible. My advice is don't go for those electronic store chains, they are a huge rip off( and for chumps), you're better off getting a laptop from sites like...

yeh that's what i was thinking, it always intersects at x = 0 hence there will always be a solution reqardless of p, i think study buddy misinterpreted the question.

During a fire drill i was returning to my locker to put my books back cause i knew it wasn't a real fire drill when a teacher turned to me and said: [I]what the hell are you doing? for all you know, you could be on fire right now!

How'd it go? Traumatic experience? I hear there's alot of competition for places

ah okay i understand now - very smart

you have to complete the square for 2 x = y + 1/y xy = y^2 + 1 y^2 - xy = -1 (y - x/2)^2 - x^2/4 = -1 y-x/2 = (x^2/4-1)^1/2 y = (x^2/4 -1)^1/2 + x/2 1. is similar but a bit more messy you have to factorise x before completing the square

isn't the inverse function y = 1 + root(4x - 7) ? why do you take the negative root? I was afraid i was missing some important formula or something the solutions say as the first step of working : If a<1 then f(a) = f(1+(1-a)) = f(2-a) since x = 1 is the axis of symmetry anyone care to...