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thanks for your help...but at the beginning of the exercise, it does say: "This course requires that even problems where the acceleration is constant must be solved by integration of the acceleration function. Many readers will know three useful equation for motion (which includes the one...

A car moves along a straight road from its front gate, where it is initially stationary. During the first 10s, it has a constant acceleration of 2m/s^2, it has zero acceleration during the next 30 seconds, and it decelerates at 1m/s^2 for the final 20 s. how far does the car go altogether? so...

ok. thanks very much for your help :) i was depressed with this english mark. :( hopefully i will be able to do well in the future.

hm...if my school is ranked in the top 20?

actually i did okay for the first assessment which was worth 15%. got 30/36. but the second assessment which was worth 25%, i got lower than 50%. but i think my ranking is near the bottom of the grade. i do maths ext 2, chemistry and economics. i'm doing alright in those ones.

If i failed (less than 50%) my 2U english school assessments and everyone does well in my school so that i'm practically ranked last after completing 40% of the school assessments, is there still a chance that i can get a band 6 in the final hsc for 2u english? and will i still be able to get...

If i failed (less than 50%) my 2U english school assessments and everyone does well in my school so that i'm practically ranked last after completing 40% of the school assessments, is there still a chance that i can get a band 6 in the final hsc for 2u english? and will i still be able to get...

How do I integrate 2^(log x)? the textbook gave a little hint: "e^(log x) = x, so what is 2^log x?" the hint didn't really help me. :uhoh: please help. thanks in advance.

Given the parametric equations x = e^t.cos(t) and y = e^t.sin(t), show that dy/dx = tan(t+pi/4). What i did was: e^t = x/(cos(t) so y=x.sin(t) / cos(t) dy/dx = tan t i'm not sure how to get tan(t + pi/4) please help. thanks.

ah...i see now. i didn't know they were the radius and the angle subtended. thanks a lot. :D

the moon subtends an angle of 31' at an observation point on Earth 400 000 km away. Use the fact that the diameter of the moon is approximately equal to an arc of a circle whose centre is the point of observation to show that the diameter of the moon is approximately 3600 km. Please help. thanks...

so it says: Sketch y = x^2 and mark the points A(a, a^2), B(-a, a^2), P(a,0) and Q(-a, 0). a) show that the integral from 0 to a of x^2 dx (sorry, can't insert the sign) = 2/3 (area of triangle OAP) b) show that the integral from -a to a of x^2 dx = 1/3 (area of rectangle ABQP) i'm not sure...

i was just wondering...if i was ranked poorly at school but do extremely well in the HSC, will i end up getting a high ATAR?