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Sry I won't be a punching bag for your sexual frustration.

Keep your fantasies to yourself. This is a subject review thread. ITT we review subjects.

Re: HSC 2014 4U Marathon ftfy

Re: HSC 2014 4U Marathon Why would you ever need L'Hopital's rule in the HSC? Are you referring to the sinx/x? If you are then I'm very sorry for you.

Re: HSC 2014 4U Marathon It's from my head?

Re: HSC 2014 4U Marathon $Using de Moivre's theorem (\cos \theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta), $show that for positive, even integers $ n$, \cos(n\theta) = \sum_{k=0}^{n/2} \binom{n}{2k} (-1)^k\sin^{n-2k}\theta\cos^{2k}\theta $ \\and derive a similar expression for $...

Re: HSC 2014 4U Marathon Fawun here's an easy one: $Prove, using mathematical induction, for $ n\ge1 $ that $ (\cos\theta + i\sin\theta)^n = \cos(n\theta) + i\sin(n\theta). $Generalise this formula for negative values of $n. $Does it make sense to extend the possible values of $ n$ to the...

Re: HSC 2014 4U Marathon Such strong maff.

Re: Students taking easy subject options says SCEGGS Darlinghurst principal Jenny All Agree with her on some fronts. But, there are still many students who take 'difficult' subjects e.g. mx2, mx1, language extensions just for the scaling, but this is a related but different matter.

Such illusion. Much wrong. That populare.

I agree with someth1ng that you need to be really comfortable with lots of hard integrals, uncertainties and lots of algebra for success in phys1902. It's quite overwhelming.

That's my rep cunt. 1v1 in front of carslaw now

Its k rep me still.

I am the second face of asianese. ----------------------------------------------------- MATH1003 - Integral calculus and Modelling Ease - 7/10 Not very difficult overall. If you've done 4 unit maths in high school, it shouldn't be too difficult. Like 3/4 of the course was just trying to...

Sozza, I had to possess another person's account. Aysce is dead ie. I changed his pw and I can't recover it LOOOOL! How is life? I know right? I never see you because you're at UNSW - it's been like...more than a whole year ahah :'( Hope things are going well though! :)

Re: HSC 2014 4U Marathon That kind of question lends itself to a generating function type approach, as you have done Realise.

Sick copy, Rythen. Hash

Ew.

Re: HSC 2014 4U Marathon I'm talking about assuming what was to be proved.

Re: HSC 2014 4U Marathon Awkward moment when the first proof is: \dfrac{a+b}{2} \ge \sqrt{ab} which start off with $Squaring, $ (a+b)^2 \ge 4ab $ which is equivalent to $ (a-b)^2 \ge 0 $ which is true. Thus the original statement is true.$