Search results

The required UAI for the courses that you would LIKE to do ranges from 76-95, yet you would prefer to get 94.6? :p

'Sif you wouldn't just run to the toilets if you were busting that bad. :confused: Better than pissing yourself in a hall full of your peers.

I think it's 87.05. Not too much pressure, thankfully.

uh, not really. :lol: The HSC isn't really about intelligence, just about trying to memorise as much as you can.

I've recently decided to do engineering as well :wave:. woot

type in sup instead of sub

Pretty sure that means you get too much sleep. I normally get to sleep around 12, 12:30 and wake up around 6.

wat

x = 2y/(1+y2) x(1+y2) = 2y x + xy2 = 2y xy2 - 2y + x = 0 y = (2±√[4 - 4x2])/2x = (1±√[1 - x2])/x

Q2. lMINOR ARC AB = r@ = 2ar [lCHORD AB]2 = r2 + r2 - 2r2.cos(2a) = 2r2(1-cos(2a)) lCHORD AB = 2r.sin(a) [using cos(2a) = 1 - 2sin2(a)] Hence: K.[2r + 2r.sin(a)] = 2r.sin(a) + 2ar => K.[1 + sin(a)] = sin(a) + a K + K.sin(a) = sin(a) + a K + K.sin(a) - sin(a) = a K + (K - 1).sin(a) = a

d/dx[sin(f(x))] = f'(x).cos(f(x)) and if f(x) = e2x then f'(x) = 2e2x So then d/dx(sin(e2x)) = 2e2x.cos(e2x)

(b) sin2Θ = 2sinΘ.cosΘ Let cos-1(3/5) = A => cos A = 3/5 - Same procedure as before, sketch a triangle where cos A = 3/5, then sin A = 4/5. Then sin2A = 2sinA.cosA = 2.(4/5).(3/5) = 24/25

You tested the second derivative there, better just change it so the OP understands.

Just a moment I will post up my solution soon. EDIT: http://img504.imageshack.us/my.php?image=mathssolutionae8wv6.jpg

x2 + 4y2 = 9 (1) 2y = 3x - 1 (2) From (2), 4y2 = (3x - 1)2 Substitute this into (1): x2 + (3x - 1)2 = 9 and solve from there.

Uh, lyounamu, read Q2 again, it asks for f'(1). You only found the derivative: f'(x) = 1/(2x-4) => f'(1) = 1/(2-4) = -1/2 EDIT: Nope. Your method would work for the derivative of logex but the general rule is that d/dx (logef(x)) = f'(x)/f(x).

SAME. I was ecstatic that all my exams are in the morning. I'm so happy with my timetable :D.

Re: 回复: Make "x" the subject

t = 0.5loge(2x-1) et = e0.5loge(2x-1) et = eloge(2x-1)0.5 2x-1 = e2t x = (e2t+1)/2

It's a pretty selective intelligence, nonetheless. This is very different from 'natural intelligence', which doesn't really have much of a connection with how much study you do, and it's this that people make a fuss of which results in the poor person's embarassment when they stress out and...