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imo tutoring for 4unit is different from tutoring 2/3u or sciences, you can't teach the train of thought required, only teach them what happens and why it happens unitl they can adopt their train of thought to that level. so no, it's not spoonfeeding really.

There was a question similar to this in one of the previous threads. The correct answer is B) 6 years. THis is because in the frame of reference of the spaceship, he is 'statoinary' and earth is moving away from him at 0.8c, thus when he views a clock on earth - it would appear to go slower.

nah i think the vector z would have a greater magnitude but no change in argument (think of 1+i, if it becomes 2+i, the modulus changes)

so what? because i'm young i'm unable to get involved in topics that i have more than an ample amount of knowledge on?

i find it pretty small.

i'm not 100% sure, but if you think about it. if z = x+iy, it has all the arguments, I don't see an effect of adding 1 to it changing the overall domain of the arguments?

|w| = sqrt[(x+1)^2 + y^2] when you let w = x+iy argument should be -pi < x < pi as i don't see the +1 having an effect on the overall domains of the argument.

in FPS games, the sensitivity of the mouse is essential when it comes to wars and competitions.

let z = x+iy k = a+ib where a,x,y and b are real and y and b =/= 0. z+k, we have x+a+i(y+b), but since z+k is real, y+b = 0 and .'. y = -b or b = -y zk = ax + ixb + aiy - yb that is, xb + ay = 0 as zk is real. from y = -b xb - ab = 0 b(x-a) = 0 x-a = 0 x = a Gathering it all...

in year 9? okay.

dont worry, by the time im' in year 12 i will rip you all at maths. i probably already do.

don't hate me because i'm better than you at mathematics you peasant.

i had the diamond razorback for cs, along with steelpad - it has served me well. costs 200ish bucks though (in total)

Practical* Compulsory* You need to improve your English. And it's not a good idea to denounce a stereotype/generalisation by producing one of your own.

Hot Single Sane Pick 2. Discuss.

Re: [-- Official 2008 HSC Chemistry Pre-exam Study Thread --] Evaluate the significance of the Haber process whilst considering the context within it's invention.

There is no constant term here. So 0 ? (3x+ (2/x^2)^9 k = 12->0 ∑ 12Ck (3x)^k*(2x)^-2(12-k) x^0 for a constant term. x^k.x^(-2(12-k) = x^0, equating powers. k-24+2k = 0 3k = 24 k = 8 Plugging k = 8 into 12Ck (3x)^k*(2x)^-2(12-k) we get the constant to be 12C8.(3^8).(2^4)

first of all, its THETA, not theatre. if you're missing an x in the isec@, then use quadratic formula otherwise do what ndependantz said.

the paper should be hard. set the dumbshits into their place and allow the bright kids to score/earn their rightful marks/results.

12y = x^2 y = x^2/6 dy/dx = 2x/6 = x/3 x = 6 at point(6,3) dy/dx of tangent at given point = 6/3 = 2, but we want normal so dy/dx = -1/2 y - 3 = -1/2 *(x-6) 2y - 6 = -x + 6 2y + x - 12 = 0 since y = x^2/12 sub this into the equation of normal and solve.