You have 5 odd numbers. Now since they can only be arranged in the order 1,3,5,7,9; then you select 5 places for the 9 [i.e. 9C5]. Now theres 4 remaining spots for the even numbers. SInce they dont have to be in any order, they can be arranged in 4! ways. So the solution:
= 9C5 x 4!
= 3024