I'll just give you hints.
1) Use discriminant, which has to be less than 0 such that it has no roots.
2) let X= 5^x (it's reducible quadratics)- Solve 5X^2-26X+25=0
I might be wrong but this is what I think (replaced y with c):
ii) LHS= a^n+3 + b^n+3 + c^n+3 + k(a^n+1 + b^n+1 + c^n+1) + a^n + b^n + c^n (expand and simplify. Note: a^n+3 = a^3 x a^n
= a^n(a^3+ka+1) + b^n(b^3+bk+1) + c^n(c^3+kc+1)
= a^n(0)+b^n(0)+c^n(0) since a,b and c are...
Don't get throw off by the phrase "monotonically increasing". It's just asking "for what values of x is the curve always increasing".
y'=3x^2-6x-27
3x^2-6x-27>0 (draw graph)
(3x+3)(x-9)>0
x<-1 and x>9.
1. f(x)= x^3-3x+4
f'(x)=3x^2-3
For decreasing: 3x^2-3< 0
therefore: x^2-1<0 (draw graph)
-1< x <1
2. f(x)=x^3+12x^2+45x-30
f'(x)=3x^2+24x+45
For increasing: 3x^2+24x+45>0
(3x+9)(x+5)>0 (draw graph)
x <-3 and x >-5
If you graph the inequality on a number line, you'll be able see it. Hope this...
a) let P(x)= 2x^2+x-2=0
P(0)= 0+0-2 = -2 which is negative.
P(1)= 2+1-2 = 1 which is positive.
Since there is a switch in sign, curve is continuous. Therefore, there is a root between 0 and 1.
b) P(0.5)= 2(0.25)+0.5-2= -1 which is negative.
From a), P(1) is positive. Therefore root is between...
First of all, to be blunt, do not post another one of your assignments up in the future in hope for just answers. Have a genuine attempt at least...
Studying maths...Not very happy about how I go about it to be honest haha, but I've had a fair share of good/bad experiences. I would recommend...
Correct me if I'm wrong (it's been a while since I last did area bounded x/y-axis), but OP, the example you gave must include borders otherwise the area is differing.
Hey guys, need some help and clarification. So you're asked to prove a quadratic has distinct roots- that would just be discussing that the discriminant is greater than 0. How do you go about explaining that a cubic equation and powers beyond have distinct roots? Do you have to relate it back to...
You probably won't be asked for the proof in 2u but most likely in 3&4u; for some formulas (can't think of one atm), it's best that you learn how to derive them.
Lol I know who you are :) But:
For these questions, you have to split it into cases
Given that the endpoints are (-2,3) and (6,3) -> the y ordinates don't change meaning that the equation of the parabola is in the form (x-k)^2 = +- 4a(y-k)
Latus rectum length =4a = 6--2 =8
Sub that in and one...