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Haha whatever... Some of us actually like science :D

:P

Woot! That was a nice test lol. Dont think I did much better than 65-70% ~ reasonably hard test. Hope I get a decent result... Ahh choking for time :S:S

Be considerate of others who may not yet have the mathematical understanding that you have. This forum is made to help people, not to chastise others for their lack of knowledge, and your post was certainly not helpful. Check the syllabus under graphs if you think this is not 4 unit, and not...

Yeah, it was not too bad. The questions took about 2.5 hrs for me to do, with time for revision, so yeah. Nice test.

haha why do you care nick ;) You failed haha :D

(n) is short hand for nC1.. it uses the binomial expansion theorem for probability. (1)

Hows this: (n) 0.5^n + (n) 0.5^n = 0.01 (1)...............(0) But since (n) = n and (n) = 1 ...............(1)...............(0) (0.5^n)[n+1] = 0.01 And by inspection we find that the value is somewhere between 10 and 11.

Re: Does anyone here play chess? haha yes.. such horrible blunders take time to heal webby. To make it even worse, I saw him play the other day and wondered how I couldve lost to him... Oh yeah, I need a team name for us. Fast.

Re: Does anyone here play chess? lol I agree with bob.. ugh.. Qf2

Hahaha... Good luck guys!

Take a gander at this: http://www.biblefire.com/viewtopic.php?t=12

Yep, all related.

Use integration by parts: Let I = cosec^3(x) / |cosec^3(x)dx u=cosec(x) u'=-cot(x).cosec(x) v'=cosec^2(x) v=-cot(x) / = -cot(x).cosec(x) - int[cot^2(x).cosec(x)]dx Changing cot^2(x) into cosec^2(x)-1.. = -cot(x).cosec(x) - int[cosec^3(x)] + int[cosec(x)] 2I =...

Hmm, isnt that just dy/dx = 3x^2 which is always >0, therefore an increasing function?

oi web, which division are you playin in?

Write oxalic acid as: H2C2O4 this way its much easier to see that it is diprotic, and you get a general idea of how it reacts. H2C2O4 + KOH ---> ....

lol nice one joel

Ok first off, when the change in heat is negative, that means the reaction is exothermic and is getting warmer. If we increase the temperature, LeChateliers Principle states that the equilibrium must oppose this and try to get colder, so here the equilibrium will be to the left - this is not...

I believe they are only really talking about water as the solvent here. Acidity depends on both the actually substance itself AND the solvent. For instance, Hydrochloric acid is a strong acid in water, but is a weak acid in diethyl ether.