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hence maybe Q6/7

It seems easier when you see the solutions before attempting it.

thank you

No worries :D

M=\frac{6000(1.0125)^{60}}{(1+1.0125^{12}+1.0125^{24}+...+1.0125^{60})}\\\\\\\\=\frac{6000(1.0125)^{60}}{\frac{1.0125^{60}-1}{1.0125^{12}-1}}\\\\\\=1835.68

As long as you and first are a big distance from the rest, you will be affect less by them.

I thought is was exam mark AND moderated assessment mark ???

Don't a lot of first year commerce subjects have a degree of maths in them?

Who would be bothered to make that up?

Maybe you are too relaxed and confident.

What about in terms of this question? (the first one in the thread)

Carrotsticks would you mind taking me through how to set out an "if and only if" proof, because I really don't know.

Wouldn't it be because AD=BD (equal radii of circle) Therefore Triangle ABD is isosceles So Angle ABD=90-x (angle sum of right triangle ABC) and Angle AEB 90-(90-x)=x (angle sum of right triangle ABE) But Angle BEA=Angle DAE (as shown by that other guy) Therefore z=x ???

Pgs 56 and 59

Don't the two highlighted things kind of contradict each other? What if you haven't finished your goals before two hours, then you can jump on the computer.

You don't sound stressed if your easily distracted. If you were stressed about school wouldn't you start studying as soon as you get home in fear of failing. It sounds more like lack of motivation and too much procrastination.

Correct: "students who repetitively fail our diagnostic tests will not be invited for re-enrolment." ^from the website

Capable? Wasn't the main point of tutoring originally to help the students that are less capable. It's obviously changed but that's pretty slack to only take 'capable' students imo.