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Apparently 60+ (give or take a few) is a state rank hahahaha wowwww

Whoever got 1st please PM me as well =)

I have no idea how I got so low in Q16 haha, I thought I answered a lot of it, especially the complex numbers part

When will we get to know our individual marks?

Re: HSC 2013 4U Marathon $i) Re-arranging the property of the polynomial$ P(k) = \frac{k}{k+1} \Rightarrow \ \ (k+1)P(k) - k = 0 \ \ \ $for$ \ \ k=0,1, \dots , n We are being asked for the roots of the polynomial (x+1)P(x) - x = 0 So, basically, for what values of x will that equation...

Re: HSC 2013 4U Marathon Link doesn't work 1. Take the natural logarithm of both sides 2. Split it up using log laws 3. Differentiate 4. Simplify

Re: MX2 Integration Marathon Yep --- \int_{0}^{\pi /2} \frac{1}{1 + (\tan x)^{\pi}} \ dx

Re: MX2 Integration Marathon That is essentially it, a better substitution would be, x= ((u-a)^2 - b)^2 but it doesn't make too much a difference \int \cos x e^{\sin x} \ dx = e^{\sin x} + c ---- \int \sqrt{\frac{1-x}{1+x}} \ dx

Re: HSC 2013 4U Marathon Yea well done (someone post a question please)

Re: HSC 2013 4U Marathon $Approximate without the use of a calculator$ \ \ \tan^{-1} (2)

Re: MX2 Integration Marathon \int \sqrt{a+\sqrt{b+\sqrt{x}}} \ dx

Re: HSC 2013 2U Marathon Yea well done $i) The point$ \ \ P(a, b) \ \ $lies on the function$ \ \ y=\sqrt{1-x^2} $Find the equation of tangent to the function at$ \ \ P $ii) Hence prove that the tangent to a circle is perpendicular to the radius$

Re: HSC 2013 2U Marathon I'm unable to do this integral can you please help me and post your solution right now ----------- \int_0^{\pi /4} \tan^2 x \ dx

Re: HSC 2013 2U Marathon \sin^2 89^{\circ} = \cos^2 (90 - 89)^{\circ} = \cos^2 1^{\circ}

I see, nothing special we need to know about parabola though right?

Is there a reflective property for hyperbola and a PS + PS' sort of thing?

Thanks!

Re: HSC 2013 2U Marathon Nice!

What Geometric properties of Conics do we need to know?

Got 2012 MX1 Q1 MC wrong The question asked to prove, A > B, I proved A > B, and concluded by writing down that A < B, losing the mark In a 2U exam last year I managed to get one of the very first questions wrong, those ones where they ask you to simplify something really simple Recently in the...