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  1. Sy123

    Official BOS Trials 2013 Mathematics Papers: Parramatta Library.

    Is the test significantly easier than last year, or only a little easier? Estimated E4 cut off?
  2. Sy123

    HSC 2013 MX2 Marathon (archive)

    Re: HSC 2013 4U Marathon 0<p , \ 0 < q p+q < 1 $Prove$ (px+qy)^2 \leq px^2 + qy^2
  3. Sy123

    HSC 2013 Maths Marathon (archive)

    Re: HSC 2013 2U Marathon $Solve the equation$ x^2 -6x + \frac{3}{x^2-6x+3} = -1
  4. Sy123

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread $By taking the fact that$ (1+x)^n = (1+x)(1+x)(1+x) \dots (1+x) $Prove the Binomial Theorem$
  5. Sy123

    A bit of help please!

    There should be 8 solutions it seems from graphing them in geogebra \cos(\pi/ 2- 4x) = \cos 3x Now we use sum to product formula: -2\sin \frac{3x + (\pi /2 - 4x)}{2} \sin \frac{3x - \pi / 2 + 4x}{2} = 0 Which is easy enough to solve, for the first one: \frac{-\pi}{4} \leq \frac{\pi /2 -...
  6. Sy123

    A bit of help please!

    Try letting z = \cos \theta + i \sin \theta
  7. Sy123

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread If you write it in summation notation it becomes easier to understand, so this is the general sum: S_{n} = \sum_{m=1}^{2^{n} -1 } \frac{1}{m} We need to prove that S_n > \frac{n}{2} For n = k (just like normal) $assume true$ \ \ S_k = \sum_{m=1}^{2^{k}...
  8. Sy123

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread Yep
  9. Sy123

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread Say I have a sequence of terms s_1 = a_1 + a_2 s_2 = a_1 + a_2 + a_3 + a_4 s_3 = a_1 + a_2 + a_3 + a_4 + a_5 + a_6 and so on, so that means: s_n = a_1 + a_2 + \dots + a_{2n-1} + a_{2n} So when we do s_{n+1} then, how many extra terms are we adding on...
  10. Sy123

    Solving for x - exponential equations to base e

    I don't know if that is the official jargon for doing: a= b to raise both sides by 10 is 10^a = 10^b But I use those words to explain it Just think about what a logarithm means, a logarithm is the opposite of exponentiation, so to get rid of a logarithm, we simply exponentiate, this is...
  11. Sy123

    Solving for x - exponential equations to base e

    just do what you normally do when solving for a \ln a = b What would you do normally? raise both sides by e a = e^{b} Similarly: \ln(\ln x) = 1 \ln x = e and then.......
  12. Sy123

    Economics essays word count

    Alright thanks guys, I'll try to be a bit faster at short answers then if some people are hitting an hour for each!
  13. Sy123

    Economics essays word count

    So the recommended words for an economics essay is 800 words according to the board of studies. Is this just an average? If we want to aim for 18+/20, should we keep it at 800 words to be succinct or should we go to about 1000-1200 words because I usually have a lot of time remaining after...
  14. Sy123

    A bit of help please!

    This probably goes too deep into the definition of a constant and a variable and isn't really something I can explain (maybe someone else could shed some light on this). From what I can tell with my limited knowledge: When we differentiate, f(x) = ax + b, and we get f'(x) = a, why can't we...
  15. Sy123

    A bit of help please!

    Don't think of y is as a variable. Consider the function: f(x) = e^{x-1} - xy + y\ln(y) f'(x) = e^{x-1} - y f'(x) = 0 \ \Rightarrow \ \ x = 1 + \ln y f''(1+ \ln y) = e^{\ln y} = y $Since$ \ \ y > 0 \ \ \therefore \ \ f''(1+\ln y) \ \ $is a minimum$ \therefore \ \ f(x) \geq f(1+\ln y)...
  16. Sy123

    HSC 2013 MX2 Marathon (archive)

    Re: HSC 2013 4U Marathon Ahhh ok ============= Something a little easier: For a triangle ABC, with point P, Q, R on AB, BC, CA respectively Such that, AQ bisects BC, CP bisects AB, and BR bisects CA. These 3 lines intersect at 1 point (a property which you may assume), at a point K, this...
  17. Sy123

    HSC 2013 MX2 Marathon (archive)

    Re: HSC 2013 4U Marathon $We establish$ \frac{1}{2} < \frac{n+2}{2n+2} < \frac{3}{4} \ \ \ (*) $for$ \ \ n \geq 1 $Consider the sequence$ \ \ b_{n+1} = \frac{3}{4} b_{n} + 1 \ \ \ b_0 = 1 $By repeated iteration, we find$ b_{n+1} = 1 + \frac{3}{4} + \dots + \frac{3^n}{4^n} +...
  18. Sy123

    HSC 2013 MX2 Marathon (archive)

    Re: HSC 2013 4U Marathon S_n = \sum_{k=0}^{n} \binom{n}{k}^{-1} S_{n+1} = 1 + \sum_{k=0}^n \binom{n+1}{k}^{-1} \binom{n+1}{k} = \binom{n}{k} \times \frac{n+1}{(n+1) - k} \therefore \ \binom{n+1}{k}^{-1} = \left(1- \frac{k}{n+1} \right ) \binom{n}{k}^{-1} S_{n+1} = 1 + \sum_{k=0}^n...
  19. Sy123

    HSC 2013-14 MX1 Marathon (archive)

    Re: HSC 2013 3U Marathon Thread $Let$ \ \ r=\frac{p}{q} \ \ $for integers$ \ \ p, q \ \ $with no common divisor except$ \ \ \pm 1 y = x^{p/q} y^q= x^p $Since we have proven$ \ \ \frac{d}{dz} z^n = nz^{n-1} \ \ $and we assume chain rule$ \frac{d}{dx} y^q = \frac{d}{dx} x^p q y^{q-1}...
  20. Sy123

    HSC 2013 MX2 Marathon (archive)

    Re: HSC 2013 4U Marathon Practising for the BOS trial? :P (btw that was HSC 2007 4U 13 marks compressed). $You may use the fact that$ \sum_{k=1}^{\infty} \frac{\sin(k\theta)}{k} = \frac{\pi}{2} - \frac{\theta}{2} $Prove that$ \pi = 3 + \frac{4}{2 \cdot 3 \cdot 4} - \frac{4}{4\cdot 5...
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