I think 5/2, will write proof in a sec.
$First, we observe that since: $\frac{2Y_n}{2X_n+1}\leq \frac{Y_{n+1}}{X_{n+1}}\leq \frac{2Y_n+1}{2X_n}$, and both sequences tend to $\infty$, it suffices to establish the result for one parity.\\ \\ To this end, we define...