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Im hoping there would be a MX1, not just a MX2 trial. Also do I have to come to some special meat to be able to get one of these, or do I buy it, or is it public?

What do you guys do in the morning, the day of an important exam? Do you guys do anything to help you keep fresh, eat a big breakfast, had x amount of sleep, etc. I need suggestions to be able to keep my mind fresh and sharp till the afternoon

Tomorrow is trial 2 for 3U math, this is the last chance I have to have a stab at first place its a slim chance, a very slim chance, Im just going to go into the exam room tomorrow, hoping that it is the hardest 3u exam that our cohort has ever sat, and then somehow pull 97+ (while everyone else...

No, since we know that if v is in terms of x (\frac{1}{2} v^2 \frac{d}{dx})=a So what you do is, you manipulate v=1/x, into that form above, then sub in x=0.5 \frac{1}{2}v^2=\frac{1}{2x^2} \\ (\frac{1}{2} v^2 \frac{d}{dx})=\frac{-1}{x^3} \\ a=\frac{-1}{x^3} \\ x=0.5 \rightarrow a \\ \\ a=-8

Using the triangle formed using alternate angles on the angle of the projection, its in my working out

If we are taking origin as (0,0) and that t=0 when projectile is fired, when t=0, the position of the aircraft is at B, not at A, so we need to find AB as well if that makes sense, its like integrating \dot{x}=U And then finding +C (or k)

Answers: Part ii Part iii

2^{2x}-6(2^x)+8=0 \\ let \ \ u=2^x \\ u^2-6u+8=0 \\ (u-4)(u-2)=0 \\ u=4, \ \ u=2 \\ \therefore 2^x=4 \ \ 2^x=2 \\ \\ \therefore x=2 \ \ x=1

Does your name appear in q1? or did you actually contribute with an idea for a question?

I reckon you should be aiming for at the very least top 3 for Standard, due to you having a not spectacularly ranked school + huge cohort + because its Standard. Im pretty sure top 3 will net you a band 5 at least (depends on externals too, but you need to have a good rank)

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un Thanks for the heads up spiral

Re: MX2 Integration Marathon Differentiating your answer leads to a result which isnt the integral (and subbing in 1 radian to both the differential of your answer, and the function that you integrated has different results)

Domain is the x values that can be x, for instance in f(x)=\sqrt{x} Our domain is x \geq 0 The reason why this is, because for any real numbered x, it cannot be negative otherwise undefined, in a similar sense f(x)=x \sin^{-1} {x^2} Well what cant x be? We know that x^2, no matter what...

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un You will probably never meet this in preliminary unless your teacher decides to be really nasty and teach it, and then put it in the test. But here is how it works, referring to my above 'formula' if you...

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un Dont worry I dont know how to do that polynomial via inspection either, either way just use u=x-1, find a factor by substituting different factors of the constant, then use polynomial division, factorise and...

Thanks to people who helped. Ill stop hijacking this thread now

Do they have a goal for a number of people each year to end up with like 100? For example if 5 people get 100 Raw we will give them 100, and then everyone else below will get 99 and below. Or only 3 got 100 raw, so we will give 100 scaled to both the people who got 69/70 and 70/70 ?

99 Raw most probably 100?

Externally raw what would achieve you 100 or 99?

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un Finding Domain is obvious for hyperbola, its pretty much what x can be, so what we are looking for is what x cant be. For \frac{x-1}{x-3} x cannot be 3. Therefore our domain is all real x, x \neq 3 For...