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Would carrot's sum of roots be necessary though? Equating the normal and the parabola will give us P and Q no matter what (because vertex is not counted), so arriving at the equation given would mean that Q has to be one of the roots?

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un Absolutely excellent method, Im pretty sure in one the HSC Q7s for 3U they ask you to make your own quadratic equation based on Projectile Motion where you are given the sum of two things and the product of...

We know that the normal at P will have two solutions one solution will be P and the other will be Q. Now finding the equation of the normal at P, I assume you know how to do this, simply differentiate subsitute x=2ap, find negative reciprocal of it to find gradient of normal, using point...

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un x^4=(x^2+Ax+2)(x^2+Bx+2) \\ \\ x^4=x^4+x^3(A+B)+x^2(AB+4)+x(2A+2B)+4 \\ \\ \therefore A+B=0 \\ AB+4=0 \\ A=\frac{-4}{B} \ \ into \ \ A+B=0 \\ \\ B- \frac{4}{B}=0 \\ B^2-4=0 \\ \\ B=2 \\ A=-2 Right? Doesnt...

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un Is the answer 2 and -2?

Re: ITT we help examine to get 85 in his Maths extension 1 yearlies so he can do 4 un x^2=9a^2 p^2 ... \ \ \ [1] \\ y=2ap^2 ... \ \ \ [2] [1] \div [2] \\ \frac{x^2}{y}=\frac{9}{2}a \\ y=\frac{2x^2}{9a} Just another algebraic approach to it incase you need it for future use.

This should probably go to the ATAR calculation section but I dont want to make another whole thread just for me whining. On average what do 99.95ers get as their HSC mark (all moderated and stuff) For example if I did: 4U Math 3U Math Ext 1 Eng Adv Eng Economics Chemistry Physics My second...

Re: The Nonsense Thread Thats enough for me I guess. Gnight

Re: The Nonsense Thread I liked to nudge the person next to me in class and ask: 'What's 2 \div 0 ' And then show them the result on the calculator Those were the days...

Re: The Nonsense Thread I lost 3 marks in the HYE because of this :/ The HYE was also the reason I got bumped down to second from first. So after I do the test I make sure I do all the questions. EDIT: Sorry no more school talk :(

Re: The Nonsense Thread I did this for trial 1, I found no mistakes whatsoever which was suspicious, and the reason why this is, is because I made the same EXACT numerical mistake the first time I did it :s Hopefully I dont do this again

Re: The Nonsense Thread I was planning to go sleep at 10:00, too late?

Re: The Nonsense Thread Tomorrow Trial 2 for 2U Math any tips for looking for the undetectable silly mistakes? Most likely will be easy since the paper will be bought. (Maybe Ill get surprised)

This was it for me.

Re: The Nonsense Thread Macs are good personal mainstream computers for the average person to facebook and stuff. Macs are absolutely crappy for everything except this: From working to gaming macbooks are absolute dungheaps of wasted money into a horrible device that is planned to be outdated...

Re: Math help (Because Carrot made me do this) Well didnt your teacher tell you that, that is what even and odd functions are? Odd functions are functions which where if you rotate about the origin 180 degrees, then you still have the original function, that is the definition of an odd...

Because 2 \times \frac{\pi}{8} = \frac{\pi}{4} And we know that \cos \frac{\pi}{4}=\frac{1}{\sqrt{2}} We know this due to the exact ratios the right angle triangles make when both their angles are 45 degrees (you surely must know this)

\frac{1-\cos 2x}{1+\cos 2x}=\tan^2 x \ \ \ $From a$ \\ \\ x=\frac{\pi}{8} \ \Rightarrow \frac{1-\cos 2 \frac{\pi}{8}}{1+\cos 2 \frac{\pi}{8} } = \tan^2 \frac{\pi}{8} \\ \\ \tan \frac{\pi}{8}=\sqrt{\frac{1-\frac{1}{\sqrt{2}}}{1+\frac{1}{\sqrt{2}}}} \\ \\ = \sqrt{\frac{ \sqrt{2}-1}{\sqrt{2}+1 }}

Re: Math help (Because Carrot made me do this) To test for even or odd functions follow Carrot's design, you always have to use f(-x) to see what you get, whether it equals to f(x) or -f(x) determines even or oddness (or neither of them if none of them apply)

Re: Math help (Because Carrot made me do this) I just expanded what you gave me as f(-x) If f(-x)=-x(-x-1) f(-x)=x^2+x When we sub in -x, its like subbing in any other pronumeral, for example f(x)=x(x-1) f(a)=a(a-1) f(-x)=(-x)((-x)-1) \\ f(-x)=-x(-x-1)= x^2+x Putting a minus in front of...