Re: HSC 2013 4U Marathon
That used to be my fastest method. I just thought of something arguably faster though.
Let a=z1-z2, b=z2-z3, c=z3-z1. Observe that a+b+c=0 always.
The equation given is equivalent to a^2+b^2+c^2=0. But since a+b+c is also zero, this is equivalent to the...