hscishard
Active Member
I'd say this question may come up in the "Quadratic Polynomial" section.Well we've done Simultaneous Equations, but I wouldn't know how to do it just from getting the coordinates haha.
You just had to know that all parabolas are in the form of: y= ax^2 + bx + c.
Therefore all you need to do is find the values of a b and c. You sub in the x and y values, which should leave 3 different a, b and c equations. (there are 3 coodinate points to sub in).
Then you solve the simultaenous equations. (3 pronumerals, 3 equations).