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Chem q (1 Viewer)

someth1ng

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The keyword is "most likely". The electronegativity difference between O (3.44) and F (3.98) is larger than C (2.55) and H (2.20).

In general, electronegativity difference will predict bond polarity: non-polar (~0), slightly polar (0-0.4), polar (0.5-2.1), or ionic (>2.1).

O-F gives 0.54; C-H gives 0.35. Therefore, more likely that C-H will be non-polar (smaller difference).
 

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The keyword is "most likely". The electronegativity difference between O (3.44) and F (3.98) is larger than C (2.55) and H (2.20).

In general, electronegativity difference will predict bond polarity: non-polar (~0), slightly polar (0-0.4), polar (0.5-2.1), or ionic (>2.1).

O-F gives 0.54; C-H gives 0.35. Therefore, more likely that C-H will be non-polar (smaller difference).
Ohh okay but how would you figure it out if you just had the periodic table since o and f are adjacent and hence seem there is a smaller difference?
 

someth1ng

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Ohh okay but how would you figure it out if you just had the periodic table since o and f are adjacent and hence seem there is a smaller difference?
A and B are group 1 metals so they generally don't form covalent bonds. C-H is a non-polar bond and is common knowledge in chemistry. You should know roughly what the electronegativity of H (2.2), C (2.5), N (3.0), O (3.5), F (4.0) is. Notice from C to F, it's just an increase of 0.5 per step?

Also, position on the periodic table is an incorrect way of thinking about electronegativity because the gap between elements will vary wildly.
 

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A and B are group 1 metals so they generally don't form covalent bonds. C-H is a non-polar bond and is common knowledge in chemistry. You should know roughly what the electronegativity of H (2.2), C (2.5), N (3.0), O (3.5), F (4.0) is. Notice from C to F, it's just an increase of 0.5 per step?

Also, position on the periodic table is an incorrect way of thinking about electronegativity because the gap between elements will vary wildly.
Ahhh makes sense thank you
 

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