is it D?View attachment 36101
how is this not c?
yesis it D?
Ohh okay but how would you figure it out if you just had the periodic table since o and f are adjacent and hence seem there is a smaller difference?The keyword is "most likely". The electronegativity difference between O (3.44) and F (3.98) is larger than C (2.55) and H (2.20).
In general, electronegativity difference will predict bond polarity: non-polar (~0), slightly polar (0-0.4), polar (0.5-2.1), or ionic (>2.1).
O-F gives 0.54; C-H gives 0.35. Therefore, more likely that C-H will be non-polar (smaller difference).
A and B are group 1 metals so they generally don't form covalent bonds. C-H is a non-polar bond and is common knowledge in chemistry. You should know roughly what the electronegativity of H (2.2), C (2.5), N (3.0), O (3.5), F (4.0) is. Notice from C to F, it's just an increase of 0.5 per step?Ohh okay but how would you figure it out if you just had the periodic table since o and f are adjacent and hence seem there is a smaller difference?
Ahhh makes sense thank youA and B are group 1 metals so they generally don't form covalent bonds. C-H is a non-polar bond and is common knowledge in chemistry. You should know roughly what the electronegativity of H (2.2), C (2.5), N (3.0), O (3.5), F (4.0) is. Notice from C to F, it's just an increase of 0.5 per step?
Also, position on the periodic table is an incorrect way of thinking about electronegativity because the gap between elements will vary wildly.