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Help with integration? (1 Viewer)

Y

Yindi

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How do they get this step, when I do it I get ln|(1+t)(1-t)| = ln|1-t^2|

thanks.
 
A

AAEldar

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I think I see what you're doing.



Remember that the minus comes out the front, then joined with the other log you get the fraction.
 
Y

Yindi

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Don't know if you're still there, but there is one more step that I just can't comprehend tonight:


Untitled.png
 
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