Y Yindi Member Joined Mar 20, 2011 Messages 43 Gender Male HSC 2012 Mar 9, 2012 #1 How do they get this step, when I do it I get ln|(1+t)(1-t)| = ln|1-t^2| thanks.
A AAEldar Premium Member Joined Apr 5, 2010 Messages 2,246 Gender Male HSC 2011 Mar 9, 2012 #2 Image isn't working!
Y Yindi Member Joined Mar 20, 2011 Messages 43 Gender Male HSC 2012 Mar 9, 2012 #4 sorry about that :S
A AAEldar Premium Member Joined Apr 5, 2010 Messages 2,246 Gender Male HSC 2011 Mar 9, 2012 #5 I think I see what you're doing. Remember that the minus comes out the front, then joined with the other log you get the fraction.
I think I see what you're doing. Remember that the minus comes out the front, then joined with the other log you get the fraction.
Y Yindi Member Joined Mar 20, 2011 Messages 43 Gender Male HSC 2012 Mar 9, 2012 #6 ahhh! thank you kindly
Y Yindi Member Joined Mar 20, 2011 Messages 43 Gender Male HSC 2012 Mar 9, 2012 #7 Don't know if you're still there, but there is one more step that I just can't comprehend tonight:
