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Is this how the HSC work? (1 Viewer)

cute lil monkey

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Is this how the hsc works, using the scenario below:

Jerry is ranked last internally in maths extension 1 out of 70 students. And let’s say in the actual HSC extension 1 exam, the lowest mark is 20%. Although Jerry through regular practical papers achieves a mark of 90% in the HSC. Therefore his raw averaged mark is now 55% which scales to an E3, 80/100. Is this true because this mark is very good for someone who ranked last in internals.

thank you very much for your time
 

WeiWeiMan

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Is this how the hsc works, using the scenario below:

Jerry is ranked last internally in maths extension 1 out of 70 students. And let’s say in the actual HSC extension 1 exam, the lowest mark is 20%. Although Jerry through regular practical papers achieves a mark of 90% in the HSC. Therefore his raw averaged mark is now 55% which scales to an E3, 80/100. Is this true because this mark is very good for someone who ranked last in internals.

thank you very much for your time
no


 

cute lil monkey

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no


still unsure
 

idkkdi

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Is this how the hsc works, using the scenario below:

Jerry is ranked last internally in maths extension 1 out of 70 students. And let’s say in the actual HSC extension 1 exam, the lowest mark is 20%. Although Jerry through regular practical papers achieves a mark of 90% in the HSC. Therefore his raw averaged mark is now 55% which scales to an E3, 80/100. Is this true because this mark is very good for someone who ranked last in internals.

thank you very much for your time
nah not quite. firstly this explanation is usually a simplication of the statistics which probably involves a distribution of some sort. also ur scaling is the aligning process done by nesa to get ur hsc marks. raw marks are instead scaled by uac in calculating your atar.

anyways, iirc, it should be ((20+x)+(90+y))/2, rather than (20+90)/2 *z. so assuming 20 -> 50, 90 -> 97 we get ~73.5.
 
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cute lil monkey

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nah not quite. firstly this explanation is usually a simplication of the statistics which probably involves a distribution of some sort. also ur scaling is the aligning process done by nesa to get ur hsc marks. these marks are further scaled by uac in calculating your atar.

anyways, iirc, it should be ((20+x)+(90+y))/2, rather than (20+90)/2 *z. so assuming 20 -> 50, 90 -> 97 we get ~73.5.
What is the x and y for the above, ((20+x)+(90+y))/2 this part, is it the number of marks that it scales to?
 

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