Tough Integration problem (1 Viewer)

[juantheron]

 

[Fus Ro Dah]

Hmm from where did you get this question? Are you sure you have typed it out correctly? I only ask because I've seen you make typos before.

 

[Sy123]

Hmm, is this an improper integral by any chance?

 

[Fus Ro Dah]

Hmm, is this an improper integral by any chance?

No, the integral is clearly convergent in the interval [0,1] by the Comparison test, not to mention the fact that it has no singularities.

 

[Sy123]

Lol, I have no idea what that means at all, I just remember reading a Wikipedia article about a month ago on this

http://en.wikipedia.org/wiki/Improper_integral

And since its an asymptote at 0. And it is an integral from 1 to 0 then I thought it was an Improper Integral.



i.e. ^^^ asymptote at c

 

[Fus Ro Dah]

Lol, I have no idea what that means at all, I just remember reading a Wikipedia article about a month ago on this

http://en.wikipedia.org/wiki/Improper_integral

And since its an asymptote at 0. And it is an integral from 1 to 0 then I thought it was an Improper Integral.

View attachment 25438

i.e. ^^^ asymptote at c

No, there is no asymptote at x=0. The function is well defined there, and is equal to 1.

 

[Sy123]

Wait a minute
I thought the denominator was (1-x^2)(sin(x)^2)

Im sorry :/

 

[RealiseNothing]

Break the denominator up into a difference of two squares, then use partial fractions perhaps?

 

[Fus Ro Dah]

Break the denominator up into a difference of two squares, then use partial fractions perhaps?

Can't do that because the numerator is a separate function class from the denominator.

 

[Nooblet94]

I got -2/pi... It seemed straightforward to me, maybe I'm doing it wrong.

Scratch that. Read it wrong.

 

[asianese]

Fus Do Rah WTF you're so ahead of the game..T_T

 

[4025808]

somethings telling me about special properties.... integral f(a-x) = integral f(x) from 0 to a

 

[mitchy_boy]

woah, glad i don't have to do this shit anymore

ive totally forgotten how to approach these things

try turning the sin^2(X) into (1-cos^2(x))???

haha gl with this mate

 

[kfnmpah]

fucking hell

wolframalpha.com

type it in, use brackets around the numerator and inside the sqrt sign and denominator. p much just bracket everything

everyone stop spamming BoS with integration q's when you can just type it in wolfram. you don't even need to know syntax just type in 'integrate xyz' and bam

jesus christ

 

[4025808]

fucking hell

wolframalpha.com

type it in, use brackets around the numerator and inside the sqrt sign and denominator. p much just bracket everything

everyone stop spamming BoS with integration q's when you can just type it in wolfram. you don't even need to know syntax just type in 'integrate xyz' and bam

jesus christ

typed in wolfram, says its not integrate-able.

 

[Carrotsticks]

fucking hell

wolframalpha.com

type it in, use brackets around the numerator and inside the sqrt sign and denominator. p much just bracket everything

everyone stop spamming BoS with integration q's when you can just type it in wolfram. you don't even need to know syntax just type in 'integrate xyz' and bam

jesus christ

Oh dear I've provided a reason against this so many times beforehand...

 

[Nooblet94]

typed in wolfram, says its not integrate-able.

http://www.wolframalpha.com/input/?i=\int_{0}^{1}\frac{\sqrt{1-x^2}}{1-x^2.\sin^2\%3Bx}dx

However, I agree that you shouldn't use wolframalpha for everything - the working it gives is absolutely ridiculously overcomplicated sometimes.