VCE Maths questions help (1 Viewer)

[boredsatan]

No

How would I solve it using these 3 values?

 

[InteGrand]

How would I solve it using these 3 values?

Try sketching the graph of the cubic. You should be able to do this once you've factorised it.

 

[boredsatan]

what's the difference between domain of R and R+

 

[InteGrand]

what's the difference between domain of R and R+

The former is all real numbers, the latter is only the positive ones (sometimes including 0, so you may need to check the convention used by the author).

 

[boredsatan]

y = -√(16-x^2)
Is there a way to find the maximal domain and also the range by inspecting the equation?

 

[InteGrand]

y = -√(16-x^2)
Is there a way to find the maximal domain and also the range by inspecting the equation?

Yes

 

[boredsatan]

Yes

how would it be done?

 

[InteGrand]

how would it be done?

Use your knowledge of basic functions. Alternatively, note that the graph is the lower-half of a certain circle.

 

[boredsatan]

Use your knowledge of basic functions. Alternatively, note that the graph is the lower-half of a certain circle.

Would drawing the graph be cheating?

 

[InteGrand]

Would drawing the graph be cheating?

No (assuming you draw it yourself, without using a computer to do it or something).

 

[boredsatan]

y = 2√(x+1) - 4
How do you find the domain and range. Quite confused

 

[boredsatan]

Could someone please explain how to do the bisection method in full detail, as I'm really confused how to do it

 

[boredsatan]

Could someone please explain how to do the bisection method in full detail, as I'm really confused how to do it

anyone

 

[InteGrand]

Could someone please explain how to do the bisection method in full detail, as I'm really confused how to do it

anyone

Did this post by Mahan1 make sense to you?: http://community.boredofstudies.org/12/mathematics/361960/maths-help-please.html#post7240008 .

 

[boredsatan]

y = √(-3x+5)
equation of inverse?

 

[boredsatan]

y = √(-3x+5)
equation of inverse?

anyone?

 

[He-Mann]

Note that -3x + 5 > 0, which means x < 5/3.

Now exchange x and y,

x = √(-3y + 5), y < 5/3

x^2 = -3y + 5, y < 5/3

y = (5 - x^2)/3, y < 5/3

Therefore,

f^{-1}(x) = (5 - x^2)/3, and f^{-1}(x) < 5/3.

 

[boredsatan]

find the angle that 3x-y=5 makes with the positive direction of the x axis

 

[InteGrand]

find the angle that 3x-y=5 makes with the positive direction of the x axis

 

[boredsatan]

would it be 18.4349488229 degrees?