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Re: MATH1131 help thread How would you know whether to use IVT or MVT? I think I'm kind of confused over that

Re: MATH1131 help thread Ok so I got the first part with IVT as you suggested, with the second part, I concluded that p2(x) has only one stationery point (-1,1/2) and its concave up, hence it can't ever touch the x axis. So can you just say because p2(x) is always positive, p3(x) can only...

Re: MATH1131 help thread Do I need to find some sort of interval to use MVT or IVT?

Re: MATH1131 help thread Me :( Managed to catch up on 2 weeks of algebra and 2 weeks of calculus this week... but just realised that I still have 1.5 ish weeks of algebra and 2 weeks of calculus left to catch up on, why am I like this fml :lol:

Re: MATH1131 help thread bos is probably going to carry me through math1131 at this rate :lol:

Re: MATH1131 help thread omg how did you get that out so quickly? I'm amazed

Re: MATH1131 help thread Ok I got part c. Trying to comprehend the first question

Re: MATH1131 help thread I'm stuck again... With the first question, I have zero clue what to do... And for the second question, I managed to do part a and part b but kind of lost with part c.

Re: MATH1131 help thread oh i see c: ty!!

Re: MATH1131 help thread I'm not understanding how the MVT can be used to prove that there is a zero. How would you do this question?

Re: UNSW chit chat thread 2017 Why would you only do three? Are you working or something?

Re: UNSW chit chat thread 2017 Haven't decided what subjects I want to take.. oh boi

Re: MATH1131 help thread Thanks!

Re: MATH1131 help thread Can someone please suggest how I should approach this?

Re: MATH1131 help thread I'm currently slogging through 3 weeks worth of maths so I'm probably going to be here for awhile... >.>

Re: MATH1131 help thread I'm following the working but in the first step, I don't understand why we're multiply by (1+z conjugate)/(1+z conjugate)

Re: MATH1131 help thread Omg thanks I got it!!

Re: MATH1131 help thread Kind of stuck on this, so I tried to equate the (1-z)/(1+z) bit and then sub in z=a+ib. And the real part simplified down to (1-2a+a^2-b^2)/(1-a^b+b^2) (if I even did this correctly). And I'm assuming since |z| =1, (a^2 + b^2) = 1. But I don't really know what to do next?

Re: UNSW chit chat thread 2017 o.O You're overloading? I think you can handle it, why tho? Are you trying to speed up your degree?

There's really no way to tell until you're older, more mature, or start working etc. it's tough... Imo the structure of SENG seems a bit more restrictive, I'd defs go for COMP over it. Yeah, I definitely see the value of having a back up. Like I was thinking that I could have commerce as a...