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That cannot be factorised, even if, it will look ugly. Please clarify the question. Do you want the solutions? solutions for x are around:-1.5, -0.4 and 0.9 Y-intercepts? y=-1 X-intercepts? x is around -1.5, -0.4 and 0.9 But these solutions for x have been found using a calculator by the...

That is mostly true, that one must have a good foundation in maths to do well in maths. I was a weird student, at the beginning of high school I knew almost all of the content (yr7&8) so i didn't do much work but still got top 10, this made me lazy and do pretty bad in yrs 9&10 going to rank...

Good to know :)

Yeah, I realised how hard harder 3u is when we started inequalities, at the beginning i was like, HOW DO WE START?! LOL. But now, i'm relatively fine with it. Induction... Not so much.

Re: HSC 2013 4U Marathon Thanks for this question :) Solution: $Subbing $(x+iy)$ and Expanding LHS and RHS:$ x^2+y^2+2y-2xi=7+4i $Equate the Imaginary First:$ -2xi=4i \therefore x=-2 $Now equate Real and Sub in x=-2$ x^2+y^2+2y=7 y^2+2y-3=0 (y+3)(y-1)=0 \therefore y=1 $ and $ y=-3...

Re: HSC 2013 4U Marathon Triangle Inequality eh spiral? Lets play around with the stuff which is given... y=tx+(1-t)z \\ \Indent \therefore t= \frac{y-z}{x-z} \\ \Indent $But we have,$ 0<t<1 \\ \Indent $So by subbing in and multiplying by denom, we get... $ 0<(y-z)<(x-z) \\ \Indent...

Re: HSC 2013 4U Marathon Thankyou :) Clearly no one pays attension to the new guy LOL :P

Can always rely on good ol' spiral. And sy LOL. U guys are crazy. lol That's pretty cool... :) I have to remember that you can do this, i've done a fair few inductions and this one's pretty special.

LOL congrats bro. Just go all out fitzpatrick and cambridge, do hard questions :)

Hmm, I see your point. When all else fails, try a traditional expansion... Step 3: Prove true for n=k+1 Assumption: k(k+1)(k+2) = k^3 + 3k^2 + 2k = 6M Proof: (k+1)(k+2)(k+3) = k^3 + 6k^2 + 11k + 6 =(k^3+3k^2+2k)+3k^2+9k+6 =(6M)+3k^2+9k+6 \therefore $ I cannot factor a 6, so it...

Lol bro ur done, the six is factored out, I'm pretty sure u can say: Since i factored a 6, it is divisible by 6

20$ defs

Re: HSC 2013 4U Marathon I'm not sure where you got this from but it is a very famous problem: Fermat's Last Theorem No way, any of us on here could probably do it... Anyways, Check it out, http://en.wikipedia.org/wiki/Fermat%27s_Last_Theorem and https://www.youtube.com/watch?v=qiNcEguuFSA...

Re: HSC 2013 4U Marathon Yeah, thanks :) Step back bro, too pro LOL Thanks, works great. :) Shii, is this mechanics already?

Re: HSC 2013 4U Marathon Alright. this might pass as harder 3u, not sure lol. It's pretty interesting for 4u anyways: Just learning latex off others haha: \fbox{1} \int \frac{secxtanx}{\sqrt{1-sec^2x} } \,\mathrm{d}x $ between b and a, where $ b>a LOL My noob latex skillz. Could...

Re: HSC 2013 3U Marathon Thread \fbox{1} \int \frac{secxtanx}{\sqrt{1-sec^2x} } \mathrm{d}x $ between b and a, where $ b>a $Hint: Use the substitution $ u=secx

Re: HSC 2013 2U Marathon Correction: 2sinx = 1 $ for $ 0 \le x \le 2\pi \\ \\ \indent sinx = \frac {1}{2} \\ \\ \indent \therefore x = \frac {\pi}{6}, \frac {5\pi}{6}

Re: HSC 2013 4U Marathon (Q1) 5-12i and 3+4i. ---------- z=4(1-i)+-sqrt(-63-16i) (After simplification) (Quadratic Formula) ---------- Delta=-63-16i Root Delta= +-(1-8i) ----------------------------- Therefore, z=4-4i+-(1-8i) z=5-12i and 3+4i (Q2) Drew up parallelogram with z1 being on real...

Re: HSC 2013 4U Marathon Wassup guys, i'm part of the 2014 cohort, how do you guys post solutions in here? Latex only? Anyways, a bit of an intro: Like I said i'm in class of 2014 and basically gonna start coming on here more often cause this forum is awesome. Subjects: 4 Unit Maths Advanced...

Guys just make peace, we all got other things to do. Just forget it :)