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When the world of humans ends, that of robots starts.

Goobi is celebrating NYE by doing integration. What about Spiral?

EE2: 4 :P MX2: 13

An ESL student in my year got 15/15 in the Belonging speech last term.

LOL What time are you arriving tomorrow?

Oh wait... did the girl say she knew you were Spiral or did you introduce yourself to her?

haha that's good then I guess? XD btw did you say hi to HIM after I left?

HIM or HER?

So far my holidays have been alright. That said, my 'holidays' end on this wednesday. After that, I have to start studying :/ What about you?

Yeah I think so haha. Did you bring two bottles? I think we stared at each other for one second or two. And then you went to toilet or something?

Hey Spiral, this is quite random but I wonder if you were in Hurstville library yesterday arvo.

Thanks Spiral. That makes more sense now :)

But I think what you said may only be true for this question as to the best of my knowledge there is no theorem to show that an irrational solution can/cannot be a multiple root. But then again, prove me wrong :P

So what do you think the question should have been worded to avoid confusion?

Thank you so much anyways :) Is it just me or did anyone interpret the question that way?

^ That's why I'm confused :(

IMO the adjective "linear" in this context is used to describe the noun "factor" but NOT the "root". Moreover, a linear factor is defined as being of the form (ax+b)... So, I wonder if I really misunderstand anything...

I am still not convinced though :( Terry Lee must have done it that way for some reason?

BTW in Ex 3.1 in the same textbook, questions 2 and 3 specifically ask for factorisations over the rational field, the real field and the complex field respectively. Therefore, as the question above actually requires factorisation over the real field, I reckon it is reasonable and logical to get...

Thanks but why do we assume that rational factors are only allowed when the question requires to get real factors (which include irrational ones)?