Search results

hmm, this makes sense

ok one question guys, on the student outline it says that ENGG1000 has 4 contact hours per week thus those red boxes seem to be addons im very confused here =S

this is mine (i just made it) if you're curious. the red parts are unavoidable =S free day on tues and ill prob skip phys lecture on fri, woo! tho i get home at like 9:30 on wednesday, but the 3 hour break makes up for it

my mistake, it was ENGG1000 attached is my finalised timetable. i cant seem to change the ENGG1000 times because thats the ONLY available option

my frikin comp1911 lecture clashes with my comp1911 tutorial. tho its the only option i have w..t..f..? i dont understand. it seems to inherently clash? how does that work

the scholarships are tax free, so i think there won't be any effect on a recipients YA someone confirm?

and if you want to bulk do exactly the opposite :p (the above statement may not be entirely correct)

Vice-Chancellor’s Equity Scholarships @ UNSW equate to 5k p.a. for four years of study

mm i think so. the ones you apply for over the internet at around the end of term 4

what i'm refering to are the ~6k p.a. scholarships given, if these exist... my friends brother got one also, the ones that didn't pass were the commonwealth start up scholarships (2k p.a. guaranteed to all youth allowance recipients) thanks

hey guys, i just realised that Equity Scholarship outcomes come out next monday. anyone here gotten one in the past? i got an ATAR of 98.4, am on youth allowance, and went to a disadvantaged PSP school (school rank low 600s last year and mid 500s this year). do you reckon i have a good chance...

\\2\int \frac{2x+2}{\sqrt{8-2x-x^2}}\,dx\\=-2\int \frac{-2-2x}{\sqrt{8-2x-x^2}}\,dx\\=-2\int \frac{f'(x)}{\sqrt{f(x)}}\,dx, \text{ where }f(x)=8-2x-x^2\\=-2\int \frac{1}{\sqrt{f(x)}}\,d\left(f(x)\right)\\=-4\sqrt{f(x)}+C\\=-4\sqrt{8-2x-x^2}+C

\\$i)$\\\\P(x)=5(x-2)(x-(1+i))(x-(1-i))=5(x-2)(x^2-2x+2) $ and expand$\\\\$ii)$\\\\$If $(x-k) $ divides $ P(x)$ then $P(k)=0\\$i.e. $3k^3 + (k+3)k^2 - (4k^2 + k - 7)k - 4=4k^2-7k-4=0\\\triangle = 103 \Rightarrow $ $2$ values of $ k$ exist such that $ (x-k) $ divides...

seems abit mixed up, try to focus on area today (if you have the time) i do, chest back legs shoulders arms in that order ^^ interspersed with 2 rest days if time doesn't allow for a split regime, consider going on the Rippetoe Regime (bodybuilding.com for more info). its a three day regime...

as an electrical engineering student, is higher phys/maths compulsory? (i'd just like confirmation)

hahahahha, best group ITT

OMG that is SO true *joins*

i've got (actually, downloaded): all of south park all of family guy all of friends all of prison break all of scrubs all of dexter all of seinfeld <3 TPG

\\x^{\frac{1}{2}}+y^{\frac{1}{2}}=a^{\frac{1}{2}}\\\frac{1}{2}x^{-\frac{1}{2}}+\frac{dy}{dx}\frac{1}{2}y^{-\frac{1}{2}}=0\\\frac{dy}{dx}=-\sqrt{\frac{y}{x}}\\$When $x=0 $ the derivative is undefined, hence there is a vertical tangent at $x=0\\$When $x=0,y=a\\$When $y=0 $ the derivative is equal...

if all turning points are above the x axis, then the absolute minimum MUST be above the x axis it thus follows that En(x) is greater than zero for all x not really a proof. give us some rigour trebla? : )