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I see :) Thanks!

Thanks! Ah it's a relief to know that there's need to waste my brain capacity remembering some random numbers :awesome:

I've heard that if you don't include temperatures for chemical equations in the HSC, you'll lose marks. Is it true though? I don't think there will be questions specifically asking for the temperatures... (well, I'm just starting Year 12 though) For example, for the equation of converting...

Parametric Question x1 1. From a point P on the parabola x2 = 2ay, a tangent is drawn. From the focus S a perpendicular is drawn to meet the tangent at R. (a) Find the equation of SR. (b) Find the locus of R. [ACTUALLY, I JUST FIGURED THIS OUT]2. Show that the locus of the middle points...

Thank you! I got it now :)

Yeah I haven't learn that XD

Thanks, I got (a) now, but still have no idea about (b). I tried to prove that angle BAX= angle CAX= x, and that angle ACX= 2*(x) but I don't know how to prove that latter part, angle ACX= 2*(x).

Thanks a lot!! For question 2, I thought you have to prove that both pairs of opposite angles add up to 180 lol, and now I realised it's a quadrilateral so if one pair adds up to 180 then the other pair must be so too. Anyone knows how to do question 1?

Hi guys, I'm having trouble with these 3 questions... can anyone please help me with them? (for question 2, only (a) thanks) Thanks in advance!

Haha I know, but he's a good teacher

I got it from my tutor. It is in the topic about geometrical application of derivative, and in the section about stationary point, maximum and minimum turning point. Here's the actual question:

Hi guys, Please help me, I need to sketch f(x)=16+4x3-x4, I've found the stationary point and division point, but I don't know how to solve for x-intercept! I tried to substitute the factors of 16 but none of them gives me y=0... Thanks in advance!

Got it, thx!!

Hi guys, I'm just wondering for (b), how should I answer it? I did this: f(-1)= -(3/-1)=3 f(2)= -(3/2)=-3/2 but that isn't answering the question (which is, "why?") isn't it? Thanks!

you and TheMathStudent :p

I see, thanks people!

Thanks for the help! but then for (b), wouldn't it be: b_n = 2 \times\ 3^{1} \times\ 3^{n-1} Then what will b_1 be? 6?

Hi all, Could someone please help me with answering these three questions with working out? (1) This one is from the hsc past papers - 1994 2U math (2) For this one, do I simply just sub n=1 and n=2 to find a1 and r? So for (d) do I do this: p1= 2-2=1/4 ; p2=2-1=1/2; so...