Search results

see below....

Consider this example then: All odd numbers are real numbers. All even numbers are real numbers. All odd numbers are integers. All even numbers are integers. All integers are real numbers. Based on your logic, can I conclude that all odd numbers are even numbers.

http://en.wikipedia.org/wiki/Circular_reasoning

Lol seriously though, ppl in this thread fail in logic

(1) - denominator is always positive (square + positive no.) so no vertical asymptotes - odd function - y=0 -> x=0 => intercept (0,0) - as x-> infinity, y-> 0, same for x-> -inf (horizontal asymptote of y=0) - you can find turning points if you want, it helps when observing...

q1: - obviously it passes through origin (odd function) - after differentiating it turns out it has no turning points. so just notice as x-> inf, the e^-x becomes insignificant, so that the curve in the first quadrant should look like e^x. reflect that about origin (odd function) q2: - no...

Implicit differentiation is really based on the chain rule learnt in 2 unit. consider y^2 d(y^2)/dx = d(y^2)/dy * dy/dx (Chain rule) dy^2/dy= 2y so hence d(y^2)/dx=2y(dy/dx) similarly for other functions of y. Q4: rearrange so that: (x^2)(y^2)-y^2=x^2 y^2(x^2-1)=x^2...

Have you dealt with differentiating exponentials in 3u yet??? d(e^x)/dx=e^x by definition.... if you dont know use your standard integral going right to left, which is differentiation.

Can you do the following questions with a calculator? a) Calculate 30% of 15000 (assume company tax is 30%) b) 15000+30400-234534+2312-(-3243223)+3242351 c) Deduct 20% of 160000 d) 1413*12+124334*23-12433124*4354 If so, you can do accounting maths. The "harder" aspects of accounting is in...

No and no.

LOL and also failed 2 subjects??

By laws of probability, I do agree with you that you can attain high 99 with any reasonable subject combination (not including stuff like gen maths and standard english, which has a superior and higher scaling versions advanced maths and english). The only issue i have is that it is much less...

Simply: HSC mark = \lceil{\frac{Exam + Assessment}{2}}\rceil

These are tips for graph of y^2=f(x) for any f(x) -If f(x)=0, then y^2=f(x)=0 then hence y=0. So the zeros of f(x) are the zeros of the new graph. - 3rd point refer to my correction. y'=f'(x)/(2sqrt(f(x)) (what you get when you differentiate y = sqrt(f(x))) so if f'(x)=0 and f(x)=0 y'= 0/...

Just a correction on my last dot point: - consider y=sqrt(f(x)), so y'= f'(x)/(2sqrt(f(x))), so when f'(x)=0 AND f(x)=/= 0 , then y'=0, so f(x) and y share the same x value of turning point (y values obviously differ)

I am also amazed why Lara wasnt picked. Tests are better entertainment for diehard cricket fans who enjoy an even battle between bat and ball and a contest of skills and endurance. 20/20 are for those who just want to see balls flying all over the park.

To sketch y^2 = f(x) based on your sketch of f(x) consider: - there will be 2 branches: y=sqrt(f(x)) and y=-sqrt(f(x)). Consider y=sqrt(f(x)) for now as the negative is merely a reflection about the x axis - if f(x)-> 0 then sqrt(f(x))-> 0 and thus y=0 so zeros are the same - vertical...

+1 If you can truly understand concepts such that you can design challenging questions testing your understanding of said concepts, you should be fine with 4U.

Note he did get state ranks in ALL his subjects and he is a certified genius in english (a hurdle for most people in attaining a really high atar) and humanities. All this tells us is that if you are a genius (like Daniel Swain), you could pull it off with most subject combos (you would not...

Back to the topic: I had to choose to do commerce and maths at Usyd or Unsw. Given that UNSW and Usyd are relatively equal in those fields, I chose UNSW on the basis of "ene mene miny mo". Since then I have not regretted anything. Whether you make your choice based on "hot chiks" or the...