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Have u found any legal articles? SMH gives me nothing :@

Hey : ]]]]]]]]]]

Thanks

Please break it down for me

:smile::smile::smile::smile::smile: Hey, how do we dy/dx a) 3^x b) 2^3x-4

tHANk you Trebla! :spin:

New Question! Don't die guys, keep answering it :guitar: 1. Identify two stakeholders in a business and how they are affected in the HUMAN RESOURCE FUNCTION. (6 marks) 2. Describe the current legal framework in the HUMAN RESOURCE FUNCTION. (10 marks)

Actually I'll do it. But what do you mean by "an operations strategy"? --> That part i shall not do. 4. Explain the main components of quality management and an operations strategy- 4 marks Quality management is when a business creates a product or provides that is always consistent by...

How do you show k >1 when you can also show k < 25/24. I found the 25/24 one.

Oh ok, well that was last year and don't expect me to remember my topic names last year.

1. Define outsourcing - 1 mark Outsourcing is the use of specialist businesses to perform functions that traditionally were performed within the business. 2. Define cost leadership - 1 mark Cost leadership is a strategy that aims to create a comp. advantage by having the lowest cost of...

I never learnt that. What r u on about. isnt that 3u?

I know both, and the roots are 2 and 3

Are you referring to the quadratic equation? or the discriminate?

Noooooooooooo-oooo, i can't think. This is too much brain power and i dont have that much brain power.

So can you give me another hint?

Thanks, im offically a dude now.

How do you get your writing like that?

2. find the exact area bounded by the curves y =sinx and y=cosx in the domain 0≤ x ≤ 2∏. Find P.O.I when you let sinx=cosx becomes tanx=1. Solutions for x= 5pi/4 and pi/4. A= integral between 5pi/4 and pi/4 (sinx-cosx)dx. = -cosx-sinx between 5pi/4 and pi/4 =[ -cos5pi/4 - sin5pi/4 ]...

For 1) SHouldn't the answer be r3 - pi/3 Area between the cuerve y=sinx and line y=1/2 under the curve =∫(sinx−1/2)dx Y= sinx When y= 0, sinx=0 and x=0 When y= 1/2, sinx=1/2 and x=π/6 and 5π/6 for 0 ≤ x ≤ 2pi Hence Area between the cuerve y=sinx and line y=1/2 under the curve =∫ from...