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  1. Michaelmoo

    Need business report question on management/ER

    Hi. Basically we've finished the "Employment Relations" topic and "Business Management and change". I can't seem to find a business report question that asseses only these two topics (or one of them). Most HSC questions include other topics such as Marketing etc, but I can't do them yet. If...
  2. Michaelmoo

    Can't answer this chem Q ><'

    Erm. I think it is related to the first two questions. Here is my answer: In this galvanic half cell, Coppers greater tendancy to ionise means that electrons are transfered from the copper half cell to the silver half cell; thus ionising (and decreasing in mass) the copper electrode. However...
  3. Michaelmoo

    Motor Effect practical???

    Ah ok. Seems like you guys made it interesting. So yeah, we did it qualitatively, just wanted to make sure it was fine because one of my textbooks actually did one similar to yours. Thanks!!!
  4. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Thats what I needed to hear. Thanks.
  5. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    I understand that. Although, you try setting y''=4x^3+18x^2+48x+24 to 0 and solve for x... Is there any possible way?
  6. Michaelmoo

    Motor Effect practical???

    Hey there. "Perform a first hand investigation to demonstrate the motor effect" Does this dot point require that we measure the exact force experienced by the object being tested (usually a current carrying element suspended off 2 retort stands). Or does it simply require us to...
  7. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Ah ok. But how would you solve that equation. I mean it does say show any points of inflexions in the original equation? So how would I find the point? Obviously the solution is not integral, but how owuld you find the exact value (or close to it)?
  8. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Ah ok Thanks. But is there ay particular way to solve that second derivative? Also, yeah I've graphed it on graphamatica, it's not on x=0 but still looks like a horizontal POI, howcome the first derivative didn't also equal 0 then?
  9. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Ok. But with this: 4x^3+18x^2+48x+24=0, how would you go about solving that? I can't seem to find an integral solution... I don't think there are any solutions.... Also, when I try graphing the original question by testign random points, I see that there should clearly be a horizontal POI at...
  10. Michaelmoo

    Parabola help!! 2 questions!

    Ok your on the right track. 1) the equation for a division of a line interval is given by x = (mx2 + nx1)/(m+n) and y = (my2 + ny1)/(m + n). I trust you've seen these equations before? Bsically you divide a line interval from (x1, y1) to (x2, y2) in the ratio of m:n internally by plugging...
  11. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Wow thanks. Erm the second last line line. I think you forgot to multiply through by four on the RHS, in that case there'd be no solution for the second derivative. I don't know why, but there must be something wrong with this question. Although when you plot it, there should be a horizontal...
  12. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    FOr the point of inflexion part: You've considered the first derivative u'v - vu' but you forgot the v^2 on the denominator? Also, howcome when you went to find the seond derivative, you didn't consider the denominator of the first derivative (v^2). Also, you didn't use the quotient rule?
  13. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Thanks, but that doesn't solve te problem. See I know how to do it but I'm not getting the answer that I should. I;ve reviewed my question and no mathematical error either. Try it yourself and see what you can get out of it.. I'm gettign no stats or points of inflexion. O and BTW, it's...
  14. Michaelmoo

    Stationary Points, Asymptotes and Points of Inflexion.

    Ok Basically the question says Find any Stationary points, Points of Inflexion or asymptotes for: y = 2x + 3 . . .(x^2 - 4) Ok so I find the asymptotes, X = plus or minus 2 and y = 0 When I try to find any stationary points or Points of inflexion, I get no solution. Although Clearly...
  15. Michaelmoo

    Would this be a legitimate complex proof??

    Anyone else think this would be considered correct? I'm still a little unsure if it would be accepted. I don't know if you could just make a substitution like that.
  16. Michaelmoo

    2007 HSC Rankings - EVERY SCHOOL LISTED.

    Wow. My school has the largest year 12 =\ Bad ranking though. Anyone know which one of these schools is the highest non-selective?
  17. Michaelmoo

    Polynomials

    Yep. I did that question two and that was the fastest method I could come up with.
  18. Michaelmoo

    should teachers teach beyond the syllabus

    I think it can be helpful, but only to clarify or reinforce a point in the syllabus. Many times even text books use this technique to help better explain a point in the syllabus, allthough it is usually footnoted when something is not needed for the HSC. Anything other than this such as for...
  19. Michaelmoo

    Wheres everyone up to?

    I actually think that's a much better way. Get the three unit out of the way so you can start focussing solly on 4-unit.
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