Re: HSC 2013 4U Marathon
Nice solution, I think my one might be yours 'in disguise' since it uses a similar concept
My one was: First conclude that at least 1 of a,b,c needs to be > 1 if it satisfies abc=1. And at least 1 of a,b,c < 1.
This leaves 2 cases, 2 of them > 1, and 1 of them < 1 or...