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Re: HSC 2014 4U Marathon Hm I'm confused myself.

Re: HSC 2014 4U Marathon It should be =n\left( \prod_{j=1}^n x_j^{p/n}\right) on the second last line

No.

Lol internal doesn't happen without external.

Pythagoras would not be impressed. :p

Um...nope.

r u sure a^2+b^2 = |a+ib|^2 = \left | (x+iy)^n \right |^2 = |x+iy|^{2n} = \left(|x+iy|^2\right)^n = \left ( x^2 + y^2 \right )^n

$Use the fact that for complex numbers $ z, |z|^n = |z^n|.

Do you think all those degrees were working? And lol Ext2 for Arts pls.

Only if you're not majoring in maths or physics.

Engineers usually do MATH2067 which is Vector Calc for engineers...as everyone has recommended - pick another degree. You are insufficiently prepared for engineering.

USYD brah - not UNSW.

Riichi or Chinese style?

2014 Goals & Resolutions: - Lower body fat and hopefully attain a slimmer and more muscular body. - Meet more people by whatever means and hopefully build deep/strong relationships with them. - Become more involved in university societies. Perhaps becoming the President of PokeSoc at USYD if...

Re: HSC 2014 4U Marathon $Using $ a+b\ge 2\sqrt{ab} $ twice on $ a, b, c, d, $ we get $ \\ \dfrac{a+b+c+d}{4} \ge \dfrac{2\sqrt{ab} + 2\sqrt{cd}}{4} = \dfrac{ \sqrt{ab}+\sqrt{cd}}{2} \ge \sqrt{\sqrt{ab}\sqrt{cd}} =\sqrt[4]{abcd}.

The approach was correct. It just involves some little tricks with factorisation: $Let $\Delta \ell $ be a small segment of the length of a curve. By Pythagoras' theorem, we have $ \\ (\Delta \ell)^2 \approx (\Delta x)^2+(\Delta y)^2\\ \begin{align*}\Delta \ell & \approx \sqrt{(\Delta...

Ppppppfffft applied :p

If i'm not mistaken you should get P(\pm2\sqrt{3},3)

Use the fact that the angles in an equilateral triangle are equal. What is alpha? Also find the length of SN. (A=N in diagram)

You can use various approaches. Use properties of equilateral triangles - all equal sides, equal angles Hint: trigonometry.