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  1. turtle_2468

    Limit problem

    But you need to EXPLAIN why it's a valid step. Without explanation many things could go down the drain... eg take a dodgy proof. The only way people could be convinced that your proof was right without you writing that bit down is by knowing that you NORMALLY would think of that step... which...
  2. turtle_2468

    Limit problem

    As long as the one you're taking out doesn't do dodgy stuff like go to 0 or infinity, I think you're fine. In this case, take out sec blah, which is a constant (ie 2)...
  3. turtle_2468

    Talented Students Day 2004

    so why did you go? btw, there is a reason people go overseas..
  4. turtle_2468

    Intergration of sqrt tanx

    you DON'T. remember, most random integrals you put down are very hard to do...
  5. turtle_2468

    "Expression of Interest" NMSS

    hmm. real maths camps are better :-P
  6. turtle_2468

    Integration q... im stuck...

    Hey! Basically you want to get rid of the top bit, since it's annoying. So letting u=e^(-x) du/dx=-e^(-x) So the integral becomes -Int(u/{1+(1/u)})du =-Int(u^2/(u+1))du =-Int(u-1+1/(u+1))du =-(u^2/2-u+ln(u+1)) =-(u^2/2)+u-ln(u+1) and sub u=e^(-x) back in. Shorter is what nike did...
  7. turtle_2468

    polynomials

    Yeah... that's about right. only 1% of this post is relevant anyway, the other stuff only serves to confuse ppl...
  8. turtle_2468

    how are these possible

    for the last time.. this is not 4U. please please post it in the extracurricular board or the commerce board or the uni board but not here...
  9. turtle_2468

    polynomials

    changed.
  10. turtle_2468

    polynomials

    lol.. should. doesn't mean there's a nice way to do it
  11. turtle_2468

    polynomials

    Moved...
  12. turtle_2468

    polynomials

    basically, reducible means having factors. The factors in say Q have to have coefficients in Q etc... ditto R and C.
  13. turtle_2468

    proving inequality with sqr roots

    1A... that brings back sweet memories..
  14. turtle_2468

    proving inequality with sqr roots

    Talking about affinity's comment...
  15. turtle_2468

    uni calculus (limits)

    alternatively, just divide both sides by x^2 a la 4 Unit then use well known things like lim of sinx/x is 1, hence lim of sinx/x^2=0
  16. turtle_2468

    proving inequality with sqr roots

    Lol, that's all 3 of us..
  17. turtle_2468

    can someone explain this to me

    so how exactly do you solve simultaneously? the point is, if you have a+b and ab, it's all well and fine, but the only way you get a, b is by solving the quadratic. You're confusing ability to solve n LINEAR simul eqn's in n variables with the ability to do it generally.... which doesn't exist...
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